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Analog Electronics – Electrical Engineering Optional PYQs (1995–2026)

Here are all 141 Analog Electronics questions asked in UPSC Electrical Engineering Optional Paper I from 1995 to 2026, arranged under the 8 topics of the official syllabus. Within each topic the latest questions come first.

Each question ends with a code such as [2024/15m/3b] – the year, the marks, the word limit (where UPSC set one) and the question number in the paper.

Topic-wise weightage graph of Analog Electronics, Electrical Engineering Optional Paper I, 2013–2026 vs 2022–2026
Topic-wise weightage of Analog Electronics (Paper I) – share of marks, 2013–2026 (white) vs 2022–2026 (black).

4.1] Semiconductor devices and equivalent circuits

21 questions

  1. For the following circuit given in Fig. (1) below, the diode has the I–V characteristic in forward direction as shown in Fig. (2): Find the (i) diode current, (ii) diode power loss and (iii) power supplied by the source.

[Figure: Fig. (1): bridge (diamond) circuit with top, left, right and bottom nodes: 2.0Ω from top to left node; 6.0Ω from top to right node; 8.0Ω from left node to bottom node; 8.0Ω from right node to bottom node; ideal-symbol diode in the vertical branch from top node (anode) to bottom node (cathode), diode current id marked downward; a 20 V battery connected between the left and right nodes (through wires running below the bridge; polarity not marked legibly). Fig. (2): diode forward characteristic id versus vd: id=0 up to vd=0.7V, then rises linearly to id=1.0A at vd=0.9V (dashed lines mark 1.0 A and 0.9 V)] [2026/20m/3b]

  1. For the Schottky transistor circuit shown below, determine IB, ID, IC and VCE. Next, remove the Schottky diode and determine IB, ID, IC and VCE assuming additional values of VBE(sat.)=0.8V and VCE(sat.)=0.1V. Assume parameter values of β=50, VBE(on)=0.7V and Vf=0.3V for the Schottky diode.

[Figure: NPN transistor with emitter to ground. Base circuit: VBB=5.8V (+ at top, − at ground) in series with RS=10kΩ to the base node; base current IB marked into the base. Schottky diode from the base node (anode) to the collector (cathode), diode current ID marked from base side towards collector. Collector circuit: collector current IC marked downward into the collector; collector connected through RC=1kΩ to VCC=5V (+ at top, − at ground)] [2025/20m/4a]

  1. Calculate the forward current caused by 0.8 V forward voltage across the diode with ideality factor of semiconductor material as 1. The reverse saturation current of diode is 12.674×10−13A at a temperature of 22°C. [Assume Boltzmann constant K=1.38×10−23JK−1, charge of electron q=1.6×10−19C]. [2022/10m/1b]

  2. Two ideal and identical junction diodes are connected as shown in Fig. 1(d). If the current through the reverse-biased diode is I0 and is constant, explain the circuit operation when both the diodes are connected in forward-biased condition. Assume VT=25mV, Vγ=0.7V and η=1 for the diodes.

[Figure: Fig. 1(d): Single series loop: a battery V = 50 mV in the bottom branch (longer plate, i.e. + terminal, on the left side); the top branch contains two diodes in series, D1 (left, voltage V1 marked above it) and D2 (right, voltage V2 marked above it), connected back to back: D1 drawn with its arrow pointing left (cathode towards the left, anode joined to D2) and D2 drawn with its arrow pointing right (anode joined to D1, cathode towards the right); the left and right vertical wires close the loop to the battery terminals] [2016/10m/1d]

  1. Silicon diodes D1 and D2 in the circuit of the figure given below have saturation current of 1 nA and 20 nA, respectively, at 300 K. Find i1, i2, V1 and V2 Given Boltzmann constant k=1.38×10−23 J/K, electronic charge q=1.6×10−19 C and emission coefficient n = 1 for Ge and 2 for Si.

[Figure: Single series loop: 6 V battery on the left (+ at top); current i1 flows right along the top wire through diode D1 (anode on the left, cathode on the right; voltage V1 across it, + on the left, − on the right); then down the right-hand side through diode D2 drawn pointing upwards (anode at the bottom, cathode at the top; voltage V2 across it, − at the top, + at the bottom; current i2 marked upwards); the bottom wire returns to the − terminal of the battery] [2006/5m/1b(iii)]

  1. “Measurement of Hall-Coefficient reveals the sign of charge carriers, thus giving type of conductivity and the concentration of charge carriers”, Explain the ‘Hall-Effect in D-type [?] semiconductors. Hence define Hall-Coefficient. [2006/20m/5a]

  2. Draw the small signal model of FET. Define μ, gm and rd, and obtain relationship between them. [2005/5m/4a(iii)]

  3. Explain varactor diode. Give its equivalent circuit. Give its application. [2005/10m/6c(ii)]

  4. Describe the band structure of an open-circuited P-N junction. [2004/20m/7a]

  5. Describe the factors on which the conductivity of intrinsic semiconductor depends. A semiconductor is made of ‘n’-type germanium. From the following data, calculate the conductivity of ‘n’-type germanium: (i) Density of Ge = 5.32×103kg/m3 (ii) At. wt. of Ge = 72.6 kg/k.mol (iii) Charge of electron = 1.6×10−9 C (iv) Mobility of holes = 0.18m2/V.s (v) Mobility of electrons = 3.8m2/V.s (Assume one donor atom in each 108 atoms) [2003/20m/4a]

  6. What is the proportion in which n-type and p-type Si both having conductivity of 10ohm−1m−1 be mixed so as to produce a fully compensated semiconductor at room temperature? Mobility of electrons and holes in Si are 0.14 and 0.05m2V−1s−1 respectively at room temperature. [2001/20m/3a]

  7. The conductivity of intrinsic Si at room temperature is 3.3×10−4ohm−1m−1. A bridge is available which can measure 1 in 104 changes in resistance. With what accuracy can this Si be used to measure the temperature in the range from 0°C to 100°C? The energy band gap in Si is 1.1 eV. The Boltzmann constant, k=1.38×10−23JK−1 and the electronic charge, e=1.6×10−19 C. [2001/20m/6a]

  8. Describe the constructional features of E-MOSFET. Calculate the voltage gain from gate to drain of the circuit shown in the above figure.

[Figure: E-MOSFET amplifier, gm=4000μ℧: a.c. source (one terminal grounded) through a 1 MΩ resistor to the gate; 100 MΩ resistor from the gate to ground; drain connected through 12 kΩ to +20 V; source connected to ground through an unbypassed 400 Ω resistor; drain coupled through a capacitor to a 48 kΩ [?] load resistor to ground] [1999/20m/8a]

  1. Draw a simple experimental set up to measure the Hall effect and show that the Hall field can be written as Ey=VXBZ where VX and BZ are the applied voltage and magnetic fields respectively. What are the typical applications of Hall effect? [1998/20m/1d]

  2. Explain the concept of Fermi-level. Sketch the Fermi-energy level for an n-type semi conductor as a function of temperature beginning at T=0∘K and going to a very “high” temp. Qualitatively discuss the nature of the characteristic. [1998/20m/4a]

  3. Consider the set up shown in the figure below for measuring Hall effect. Assume that L=10−1 cm, W=10−2 cm. The following parameters are measured: IX=1.0 mA, VX=12.5 V BZ=5×10−2 T, VH=−6.2 mV Find the type of the semiconductor, majority carrier concentration and the mobility.

[Figure: Hall-effect set-up: rectangular semiconductor bar of length L (along x, between the current contacts), width W and thickness d, lying in the x–y plane; voltage Vx (battery, + and − marked) drives current Ix along the length; magnetic field Bz perpendicular to the bar; Hall voltage VH (+ and − marked) measured across the width; fields Ex and EH and the carrier drift marked inside the bar] [1998/20m/8a]

  1. What do you understand by the forbidden gap in energy bands? Electrons are excited across the forbidden energy gap E0 in Germanium by bombarding of photons. Calculate the maximum wavelength for a photon which will produce electron-hole pairs in Germanium, if E0=0.71 eV. [1997/20m/5c]

  2. The bulk n-type region of a particular Germanium junction has conductivity of 104 S/m at 300 K and that the for the p-region is 102 S/m. Find the voltage drop across the junction in equilibrium at 300K, assuming intrinsic carrier concentration as 2.5×1019m3 mobility of electron and holes as 0.36m2/v–s and 0.17m2/v–s respectively. [1997/20m/8c]

  3. Calculate the conductivity of silicon when it is doped by an n-type impurity to the extent of 1 in 106. The atomic density of silicon is 5×1022atoms/cm3, the intrinsic carrier density is 1.48×1010pair/cm3 and the mobilities are 500cm2/V–s and 1300cm2/V–s. Compare the conductivity with that of intrinsic silicon. [1995/20m/5c]

  4. Find the CB h-parameters of a transistor in terms of its r-parameters and α. [1995/20m/8a]

  5. What is MESFET? Give its characteristics. What are intrinsic and extrinsic parameters of a MESFET? What is the effect of increasing the channel doping to a value as high as possible? [1995/20m/11b]

4.2] Diode circuits

14 questions

  1. A single-phase, full-wave bridge diode rectifier supplied from 240 V, 50 Hz AC source is feeding a resistive load RL=100Ω as shown in the figure below. Due to fault in the diode D2, it behaves like a resistance of 1kΩ. Sketch the load voltage, load current and source current waveforms under faulty condition. Also calculate the load average voltage and r.m.s. source current under this situation:

[Figure: Single-phase diode bridge: left leg D1 (upper) and D4 (lower), right leg D3 (upper) and D2 (lower); all four diodes point upward (anode below, cathode above). One terminal of the 240 V, 50 Hz AC supply goes to the junction of D1 and D4, the other to the junction of D3 and D2. Top rail (cathodes of D1, D3) to the top of RL=100Ω; bottom rail (anodes of D4, D2) to the bottom of RL] [2026/10m/4b(ii)]

  1. Draw the output voltage waveform of the circuit given below for 5 V, 50 Hz ac rms input. Forward voltage drop in diode D1 is 0.6 V.

[Figure: Two-port circuit, INPUT terminals on the left, OUTPUT terminals on the right, common lower line. Capacitor C1=100μF in series in the upper line (− plate on the input side, + plate on the output side). After C1: R1=10K from the upper line to the lower line; and a branch from the upper line to the lower line consisting of diode D1 (cathode at the upper line, anode downward) in series with a 3 V battery (+ terminal towards the diode’s anode, − terminal at the lower line). The output is taken between the upper and lower lines] [2025/10m/1c]

  1. (i) Find the value of average current flow through the load resistor for the circuit given in Fig. 6(a). (ii) Find the value of r.m.s. current drawn from the source.

[Figure: Fig. 6(a): Single-phase diode bridge. Left leg: D3 (lower) and D1 (upper) in series, both with anode below and cathode above; right leg: D4 (lower) and D2 (upper) in series, same orientation. Source v(t)=320sinωt, ω=2*π*50, connected with one terminal to the junction of D1 and D3 and the other terminal (wire crossing without connection) to the junction of D2 and D4. The cathodes of D1 and D2 (top rail) connect through a 320 kΩ resistor in series with a 160 V battery (positive plate towards the resistor/top rail) to the anodes of D3 and D4 (bottom rail)] [2017/20m/6a]

  1. Draw a circuit diagram for a single-phase, full-wave, midpoint diode rectifier. Sketch waveforms for source voltage, load voltage, voltage across one diode and source current. Take turns ratio from each secondary to primary as unity. Derive expressions for average and r.m.s. output voltages. [2010/10m/1c(i)]

  2. Determine the reading of the ideal voltmeter connected across a silicon diode shown in Fig. 9: Assume the forward voltage of diode to be 0.7 V. Find also the current through the diode.

[Figure: Fig. 9 – Series loop: 5 V battery (+ at top) – 1 K resistor – silicon diode D (anode on the resistor side, cathode on the right, i.e. forward biased by the battery) – back along the bottom line (grounded) to the − terminal; ideal voltmeter V connected directly across the diode] [2010/4m/5b(ii)]

  1. Construct circuits using diodes which exhibit terminal characteristics as shown in Part (i) and Part (ii) of the figure below. Assume diodes to be ideal.

[Figure: Two I–V characteristics. Part (i): I=0 for −V1≤V≤V1; for V>V1 a straight line of positive slope rising from (V1,0); for V<−V1 a straight line of positive slope falling from (−V1,0) into negative current. Part (ii): vertical jump at V=0 from −I1 to I1 (along the I-axis); for V>0 a straight line of small positive slope starting at (0,I1); for V<0 a straight line of small positive slope ending at (0,−I1)] [2009/20m/3a]

  1. Input voltage to the circuit of the figure given below is vin=12sint V. Determine the output voltage v0 and sketch it, What is the name of the circuit?

[Figure: a.c. source vin (+ at top); 1 kΩ resistor in the top wire from the source to node N; from node N to the bottom wire a series branch: 3 V battery (− terminal at node N, + terminal below) followed by diode D (cathode towards the battery, anode at the bottom wire); 3 kΩ load resistor from node N to the bottom wire, output v0 across it (+ at top)] [2006/5m/2a(iv)]

  1. Draw the circuit diagram of a half wave rectifier with a reservoir capacitor that smooths the output. Draw its output waveform. Determine the reservoir capacitor value for a HWR and smoothing circuit to supply 20 V to a load of 500 Ω. Maximum ripple amplitude is to be 10% [?] of the average output voltage, and the input signal frequency is 50 Hz. [2004/20m/7a]

  2. .

(i) Calculate the quiescent collector current ICQ or room temperature for the amplifier circuit shown in the figure given below.

[Figure: Voltage-divider-biased npn transistor amplifier: supply (10 ± 1) V on the top line; 4.2 k from the supply to the base node and 0.4 k from the base node to ground (the base node connected to the base); collector resistor 0.3 k from the supply to the collector; emitter resistor (100 ± 10) Ω from the emitter to ground.] [2000/10m/4b(i)]

(ii) Describe the applications of clipping and clamping circuits. [2000/10m/4b(ii)]

  1. The figure below shows a full wave rectifier circuit. For a sinusoidal input voltage, plot the voltage wave forms across R and D1. [1998/20m/4b]

  2. Select any Three of the following statements, read them carefully and identify correct and incorrect ones. Justify your answer using not more than 200 words in each case: The required PIV capacity of diodes in single phase bridge rectifier is one half than that required in rectifier using centre tap transformer. [1998/20m/200w/1d]

  3. For full-wave rectification, what circuit configuration would be preferred and why? A bridge rectifier fed through a transformer from a 230 V, 50 Hz supply is used to deliver power to a transistor radio at 9V d-c. Assuming ideal diodes and load resistance of 90 Ω, specify the turns-ratio and current rating of transformer. Also find the d-c and a-c (rms) values of Load current and Peak-Inverse-Voltage. [1997/20m/4b]

  4. In the circuit of Fig. 5a, the diode is ideal, R=1.2kΩ and I=5 mA. Draw the v – i characteristics of the circuit (i) with S open and −10 volt <v< 15 volt and (ii) with S closed and 0<v< 15 volt What happens when v<0 with S closed?

[Figure: Fig. 5a: Four branches in parallel between a top line and a bottom line: (1) voltage source v (+ at top), with current i marked in the top line leaving its + terminal; (2) switch S in series with an ideal diode, cathode towards S (top) and anode at the bottom line; (3) resistor R; (4) current source I (arrow upwards)] [1996/20m/5a]

  1. In the circuit of Fig. Q 5(b), the diodes are ideal. Determine and sketch v0(t) for 0<t<8 ms when v1(t) is a square waveform of ± 1 V amplitude, 8 ms period with a positive going zero crossing at t=0, the input v2(t) 2 sin πt/3 volt with t in ms and v3(t) is a 3 V amplitude rectangular pulse existing over 1 ms <t< 3 ms.

[Figure: Fig. Q 5(b): Three inputs v1(t), v2(t) and v3(t), each connected to the anode of an ideal diode; the three cathodes are joined to a common node, which is connected to ground through resistor R; output v0(t) taken from the common node] [1995/20m/5b]

4.3] Biasing and bias stability

17 questions

  1. For the circuit shown in the figure below, the two transistors Q1 and Q2 have β1=35 and β2=30. The resistance R2 is variable. The output voltage Vo across resistance Ro is +5.0V. If the voltage VCC is kept at +12.0V, find the value of R2. Derive any formula used. Assume VBE=0.7V for both the transistors:

[Figure: Darlington pair of NPN transistors. Supply rail VCC=+12.0V. R1=100K from VCC to the base of Q1; variable resistor R2 from the base of Q1 to ground. Collectors of Q1 (β1) and Q2 (β2) both connected to VCC. Emitter of Q1 drives the base of Q2. Emitter of Q2 is the output node Vo=+5.0V, with Ro=1kΩ from the emitter of Q2 to ground] [2026/10m/4b(i)]

  1. For the circuit shown below, early voltage VA=∞ and β=100. Find the reverse saturation current if: (i) the collector current of Q1=0.5mA. (ii) Q1 is biased at the edge of saturation.

[Figure: VCC=2.5V; voltage divider 50 kΩ (from VCC to the base of NPN transistor Q1) and 30 kΩ (from the base to ground); 3 kΩ from VCC to the collector; emitter grounded.] [2023/20m/4a]

  1. For the transistor circuit shown in Figure 1(d), determine the value of reverse saturation current, IS, that would give a collector current of 1 mA, if β=80, VA=∞ and VT=26mV at T=300K.

[Figure: Figure 1(d): pnp transistor Q1 with its emitter connected to VCC=2.5V. The collector is connected through 1.6 kΩ to ground. A 20 kΩ resistor is connected between the base and the collector (base–collector feedback).] [2021/10m/1d]

  1. A Darlington transistor pair circuit is shown in Figure 1(d) below. Both the transistors have dc current gain β of 30. In the circuit VCC=+12V, RE=1.5kΩ. (i) Find the value of R1 needed to bias the circuit such that VCEQ2=5V for transistor T2. (ii) With the same value of R1 as obtained above, determine the value of VCEQ1. Assume both T1 and T2 are Si transistors.

[Figure: Figure 1(d): Darlington pair of npn transistors T1 and T2. The collectors of T1 and T2 are both connected to the supply rail VCC; resistor R1 is connected from the VCC rail to the base of T1; the emitter of T1 drives the base of T2; the emitter of T2 goes through RE to ground] [2020/10m/1d]

  1. Find the DC input resistance at the transistor base of the circuit shown in Figure 1(c).

[Figure: Figure 1(c): npn transistor (current gain βDC) with collector connected through RC to +VCC and emitter connected through RE to ground; input voltage Vin (+ at top) applied between the base and ground, input current Iin flowing into the base; VBE marked between base (+) and emitter (−)] [2019/10m/1c]

  1. For the circuit shown in Figure 3(c), derive the expression for stability factor S(β).

[Figure: Figure 3(c): Collector-to-base (collector feedback) bias: npn transistor with collector connected through RC to +VCC; resistor RB connected from the collector to the base; emitter connected directly to ground] [2019/10m/3c]

  1. For the circuit given in Figure 6(d), comment on its operating conditions.

[Figure: Figure 6(d): pnp transistor amplifier with VCC=−30V. Rb=10kΩ from the VCC line to the base (base current IB shown flowing upward through Rb); collector connected to VCC through the primary winding of an output transformer, whose resistance is Rc=15Ω; the transformer secondary feeds the load RL; emitter connected to ground through Re=5Ω in parallel with bypass capacitor Ce; signal source Vs in series with Rs coupled to the base through capacitor C, the other side of Vs grounded]

For the transistor, β = 100 ICO=1mA (at VCB=40V) [2019/10m/6d]

  1. Determine ID and VGS for the JFET with voltage divider bias as shown in Figure 7(b). The internal parameter values of this JFET are such that VD≈7V.

[Figure: Figure 7(b): n-channel JFET with voltage divider bias: VDD=+12V; R1=6.8MΩ from VDD to the gate and R2=1.0MΩ from the gate to ground; drain resistor RD=3.3kΩ from VDD to the drain (drain current ID flowing downward; drain voltage VD); source resistor RS=2.2kΩ from the source to ground] [2019/10m/7b]

  1. With reference to a BJT, show that ∂Pc∂Tj<1θJA must be satisfied in order to prevent thermal runaway. [2011/15m/1d]

  2. For the circuit shown in Fig. 2– 1. determine the operating point; 2. find the stability factor. Given: VBE=0.6V, β=50.

[Figure: Fig. 2 – NPN transistor (β=50) in voltage-divider bias: VCC=15 V; 39 K from VCC to the base, 4.7 K from the base to ground; 4.7 K collector resistor from VCC to the collector; 1 K emitter resistor from emitter to ground; input terminal at the base (other input terminal at ground), output terminal at the collector (other output terminal at ground)] [2010/10m/1b(i)]

  1. For the circuit shown in the figure, assume β=hFE=100.

(i) Find if the silicon transistor is in cut-off, saturation or in the active region. [2009/10m/1b(i)]

(ii) Find vo.

[Figure: PNP transistor Q: collector connected through 3 K to the −10 V supply, output vo taken at the collector; emitter connected through Re=500Ω to ground; base connected through 7 K to the negative terminal of a 3 V battery whose positive terminal is grounded] [2009/5m/1b(ii)]

  1. An n–p–n silicon transistor is used in a common-collector circuit as shown in the figure below. The circuit component values are VCC=3.0V, Re=1K, R1=R2=5K. If β=44, find the quiescent point.

[Figure: Common-collector (emitter follower) bias circuit: collector connected directly to VCC=3.0 V; voltage divider R1=5 K from VCC to the base and R2=5 K from the base to ground; emitter connected through Re=1 K to ground] [2009/12m/6b(i)]

  1. For the circuit of the figure given below β=100, R1=90 kΩ, R2=10 kΩ, RC=5 kΩ, RE=1 kΩ and VCC=20 V Determine iB, iC and VCE.

[Figure: Voltage-divider biased NPN transistor: R1 from +VCC to the base node, R2 from the base node to ground; collector through RC to +VCC; emitter through RE to ground] [2006/5m/7a(iv)]

  1. List the three sources of instability of collector current Define the three stability factors. Which biasing arrangement gives you better stability? [2005/5m/2a(iii)]

  2. .

(i) Calculate the quiescent collector current ICQ or room temperature for the amplifier circuit shown in the figure given below.

[Figure: Voltage-divider-biased npn transistor amplifier: supply (10 ± 1) V on the top line; 4.2 k from the supply to the base node and 0.4 k from the base node to ground (the base node connected to the base); collector resistor 0.3 k from the supply to the collector; emitter resistor (100 ± 10) Ω from the emitter to ground.] [2000/10m/4b(i)]

(ii) Describe the applications of clipping and clamping circuits. [2000/10m/4b(ii)]

  1. The JFET used in the circuit of Fig. 4 (a) has the following data: RD=2kΩ, RS=8kΩ VDD=15 V, VG=10 V and VSS=−8 V. Assuming IDSS=5 A and VPO=−3 V for the JFET calculate VGS and VO.

[Figure: Fig. 4 (a): n-channel JFET source follower: drain connected through RD to VDD; gate G driven by the input voltage (VG, + at the gate, − at the common line); source connected through RS to VSS; output VO taken between the source and the common line] [1997/20m/4a]

  1. A silicon transistor has a β-independent bias using an emitter resistor potential divider combination. The emitter circuit resistance is 300 Ω, the collector circuit resistance is 500 Ω, collector supply voltage is 15 V and β=100. Find the potential divider resistances so that maximum symmetrical swing is permitted at the collector. Take VCE,sat=0. [1995/20m/8b]

4.4] Transistor and FET amplifiers

17 questions

  1. In the circuit given below, transistors T1 and T2 are having VBE=0.6V and β=499. (i) Calculate small signal ac voltage gain of the amplifier at 20 Hz and 2 kHz. (ii) Find dc voltages on collectors of transistors T1 and T2 respectively.

[Figure: Two-stage direct-coupled NPN amplifier, VCC=12V, common ground rail. INPUT through coupling capacitor C1=10μF (− on input side, + on base side) to the base of T1. R1=9.1K from VCC to the collector of T1; the collector of T1 is connected directly to the base of T2. R2=2K from VCC to the collector of T2. Emitter of T1 goes to node E1; R5=200E (Ω) from E1 to node F; R6=1.3K from F to ground, bypassed by C4=3.3μF (+ at F) from F to ground. R3=36K from E1 up to a wire that goes through capacitor C2=10μF (− on the R3 side, + on the collector side) to the collector of T2. Emitter of T2 goes to node E2; R7=1K from E2 to ground and C5=100μF (+ at E2) from E2 to ground; R4=100K from E2 back to the base of T1. Collector of T2 through C3=100μF (+ on collector side) to the OUTPUT node; RL=10K from OUTPUT to ground] [2025/20m/3b]

  1. Calculate the lower corner frequency for the circuit shown below. Take transistor parameters as: β=100, VBE=0.7V and VA=∞.

[Figure: Common-emitter amplifier, VCC=12V. Source vi (+ at top) in series with RS=0.5kΩ and coupling capacitor CC=0.1μF to the base of an NPN transistor. Bias divider: R1=10kΩ from VCC to the base, R2=1.5kΩ from the base to ground. RC=1kΩ from VCC to the collector; output vo taken at the collector. RE=0.1kΩ from the emitter to ground (no bypass capacitor). The − terminal of vi is grounded.] [2023/10m/1d]

  1. A common-emitter amplifier circuit is shown in Figure 3(a). Neglect rx and ro and assume the current source to be ideal. (i) Derive an expression for the midband gain. (ii) Derive expressions for the break frequencies caused by CE and CC. (iii) Give an expression for the amplifier voltage gain A(s). (iv) For Rsig=RC=RL=10kΩ, β=100 and I=1mA, find the value of the midband gain. (v) Select values for CE and CC to place the two break frequencies a decade apart and to obtain a lower 3 dB frequency of 100 Hz while minimizing the total capacitance. (vi) Sketch a Bode plot for the gain magnitude and estimate the frequency at which the gain becomes unity.

[Figure: Figure 3(a): npn BJT common-emitter stage. Signal source Vsig (+ terminal on top, − terminal grounded) in series with Rsig drives the base. Collector connected through RC to VCC (arrow pointing up); collector coupled through capacitor CC to the output node Vo, with load RL from Vo to ground. Emitter connected to an ideal current source I (arrow pointing down) going down to the negative supply (arrow pointing down), and from the emitter a bypass capacitor CE to ground.] [2022/20m/3a]

  1. The amplifier shown in Figure 4(c) is biased to operate at ID=1mA and gm=1mA/V. Neglecting ro, (i) determine the midband gain. (ii) determine the value of CS that places fL at 10 Hz.

[Figure: Figure 4(c): n-channel MOSFET amplifier. Source Vi (+ terminal on top, − terminal grounded) connected directly to the gate. Drain connected through RD=10kΩ to VDD (arrow pointing up); output Vo taken from the drain. Source terminal connected through RS=6kΩ down to the negative supply (arrow pointing down), and from the source terminal a capacitor CS to ground.] [2022/10m/4c]

  1. For the circuit shown in Fig. 2(c), calculate the resistance Ro as seen by the output terminals. Ignore the effect of R1 and R2. Assume β=99 and hie=1kΩ. Comment on the value of Ro of the circuit:

[Figure: Fig. 2(c): Emitter follower: NPN transistor with collector connected directly to +VCC; bias resistor R1 from +VCC to the base and R2 from the base to ground; a.c. source Vs (bottom grounded) connected to the base through a 1 kΩ source resistance (drawn as a coil-shaped element labelled 1 kΩ); emitter connected to ground through a 1 kΩ resistor; output Vo taken at the emitter; an arrow marks Ro as the resistance looking into the emitter/output terminal] [2016/10m/2c]

  1. Draw the circuit of a Cascode amplifier. Indicate the two configurations of transistors used. Why is this circuit preferred in high-frequency applications? [2010/6m/2b(i)]

  2. Draw the circuit of Darlington emitter follower. Obtain the expressions for overall current gain and input impedance. You can use suitable approximations. Find the above two quantities if RB=2MΩ, RE=1kΩ. The device parameters are identical. hfe1=hfe2=50,hie1=hie2=1K,hoe1=hoe2=20μA/V [2010/10m/3a(i)]

  3. Three identical cascaded stages have an overall upper 3-dB frequency of 20 kHz and a lower 3-dB frequency of 20 Hz. What are fL and fH of each stage? Assume non-interacting stages. [2009/8m/6b(ii)]

  4. The ac equivalent circuit of an N-P-N transistor circuit is shown below. Draw the actual circuit with biasing and coupling capacitors.

[Figure: Input Vi with input current Ib through resistor hie in the top wire to the output node Vo; from the output node to the common bottom wire a current source hfeIb (arrow pointing up, towards the output node) and load resistor RL in parallel; output Vo taken at the right end of the top wire] [2007/5m/4a(ii)]

  1. What is the impedance reflection principle as referred to FET circuits? Draw the circuit of a typical source follower and apply reflection principle to obtain its output equivalent circuit. [2006/5m/5b(iii)]

  2. What do you understand by Miller capacitance? For a CE amplifier following parameters are given ri=10 kΩ [?], Cb′c=4 pF, Rb=1 kΩ, Cb′e=300 pF, rbb′=20Ω, gm=0.5 S, rb′e=150Ω, RL=300Ω and RC≫RL. Determine the Miller capacitance. [2006/5m/8a(iii)]

  3. Obtain the voltage gain and output resistance of the composite amplifier shown in Fig. above.

[Figure (printed above the text): Composite FET–BJT follower. Input vi applied between the input line and the ground (bottom) line; resistor RG from the input line to ground; the input line goes to the gate of FET T1; drain of T1 to the supply VCC (top line); source of T1 connected to the base of bipolar transistor T2; collector of T2 to VCC; emitter of T2 to ground through resistor RE; output vo taken across RE (between the emitter and ground).] [2001/20m/4b]

  1. The transistor shown in the above figure has following h parameters: hie=1000Ω, hfe=50, hre=3×10−4 and hoe=5×10−5 Find the voltage gain and ac. input impedance of the amplifier. Neglect capacitor impedances.

[Figure: Common-emitter amplifier, supply +20 V: voltage-divider bias – 60 kΩ from +20 V to the base and 30 kΩ from the base to ground; input Vin applied to the base through a coupling capacitor; 10 kΩ collector resistor from +20 V to the collector; 10 kΩ emitter resistor from the emitter to ground, bypassed by a capacitor; output Vout taken from the collector through a coupling capacitor across a 30 kΩ load resistor to ground] [1999/20m/6b]

  1. Describe the constructional features of E-MOSFET. Calculate the voltage gain from gate to drain of the circuit shown in the above figure.

[Figure: E-MOSFET amplifier, gm=4000μ℧: a.c. source (one terminal grounded) through a 1 MΩ resistor to the gate; 100 MΩ resistor from the gate to ground; drain connected through 12 kΩ to +20 V; source connected to ground through an unbypassed 400 Ω resistor; drain coupled through a capacitor to a 48 kΩ [?] load resistor to ground] [1999/20m/8a]

  1. For the circuit shown in the figure below, draw the ac. equivalent circuit and find the voltage gain of the amplifier.

[Figure: JFET common-source amplifier: a.c. source (grounded) coupled through capacitor Cc to the gate; gate bias divider R1 from VDD to the gate and R2 from the gate to ground; drain connected through 100 K to VDD, output Vo taken at the drain; source grounded; device data rd=50KΩ, μ=300 [?]] [1998/20m/7b]

  1. The mid-band equivalent circuit of a common emitter transistor amplifier is shown in Fig. 4(c). The h-parameters of the transistor used are hie=1500Ω, hre=10−3, hfe=100, hoe=50×10−6Ω Find the mid-band gain iS1/ibe [?] where iS1 [?] where is the current in 5 kΩ resister.

[Figure: Fig. 4(c) (hand-drawn, partly illegible): input side – signal current source is (arrow up) with its source resistance [?] in parallel, feeding terminals B–E through a bias resistance [?]; then hie in series with a controlled voltage source hrevce; output side between C and E – controlled current source hfeibe (arrow down), 1/hoe, the collector resistor Rc = 10 kΩ and the 5 kΩ load (current iS2 [?]) all in parallel; output voltage vce between C and E] [1997/20m/4c]

  1. Find the mid-frequency gain of the amplifier shown in Fig. 8b. Neglect the loading effect of R1 and R2. The transistor parameters with usual notations are gm=0.015 S, rb′e=1Ωk, rbb′=90Ω, Cb′e=20 pF and Cb′e=3 pF while RE=1kΩ.

[Figure: Fig. 8b: Emitter follower: input source “IN” coupled through capacitor C1 to the base of an npn transistor; bias divider R1 from VCC to the base and a lower resistor (printed R5, i.e. R2 [?]) from the base to ground; collector connected directly to VCC; emitter resistor RE from the emitter to ground; output “OUT” taken from the emitter through a coupling capacitor, with respect to ground] [1996/20m/8b]

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4.5] Differential, feedback and power amplifiers

9 questions

  1. In the circuit diagram given here, T1 and T2 are transistors with matched characteristics. The transistor parameters in active region are β=200 and VBE=688mV. Find VCE of transistor T2:

[Figure: Current-mirror circuit with +12 V supply rail at top and grounded bottom rail. 560 Ω from +12 V to the collector of T1; 470 Ω from +12 V to the collector of T2. T1 is diode-connected (its collector tied to its base); the bases of T1 and T2 are connected together. Both emitters go to the grounded bottom rail. NPN transistors.] [2024/10m/1c]

  1. Consider the figure of differential pair given below. Neglecting the early effect, determine the change in VX, VY, VX−VY if (i) VCC rises by ΔV and RC1=RC2=RC. (ii) IEE experiences a change of ΔI and RC1=RC2=RC. (iii) RC1=RC2+ΔR.

[Figure: BJT differential pair: NPN transistors Q1 and Q2; RC1 from VCC to the collector of Q1 (node X); RC2 from VCC to the collector of Q2 (node Y); emitters joined and connected to a current source IEE (arrow down) to ground; both bases connected together to a common-mode source VCM (+ at top) whose − terminal is grounded.] [2023/10m/2c]

  1. Shown below (Figure 3(a)) is a differential amplifier with a three transistor active load. Draw the small signal equivalent circuit of its output stage with active load and calculate its small signal differential mode voltage gain. Assume the output impedances of the transistors Q1 to Q5 to be r01 to r05 respectively. Assume the base currents to be negligible.

[Figure: Figure 3(a): Differential pair of npn transistors Q1 and Q2 with emitters joined and connected to a current source IQ (arrow downward) to −VCC. Base of Q1 driven by a source vd2 (+ at top) to ground, base current ib1 into the base; base of Q2 driven by a source vd2 (− at top, + at bottom) to ground, base current ib2. Active load: pnp transistors Q3 and Q4 with emitters at +VCC and bases tied together; collector of Q3 connected to collector of Q1 (current i3 out of Q3, i1=gmvd2 downward into Q1); pnp transistor Q5 with base connected to the Q1/Q3 collector node, emitter connected to the common bases of Q3 and Q4, collector to −VCC. Collector of Q4 (i4=gmvd2 downward) connected to collector of Q2 (i2=gmvd2 upward); this output node is coupled through capacitor CC (current io) to the load RL to ground; output vo across RL] [2020/20m/3a]

  1. Find the efficiency of a class A amplifier shown in Figure. Given that the voltage drop across RE is 1 V, the signal current swings from −0.5 A to +0.5 A and the DC current is 1 A.

[Figure: Transformer-coupled class A amplifier: input applied to the base of a transistor; collector connected to one end of the primary winding of an output transformer (label “0.5 A” beside the primary); the other end of the primary goes to the supply marked 10 V, 1 A; secondary winding feeds a loudspeaker; emitter connected to ground through RE (1 V across it) with a bypass capacitor in parallel with RE] [2015/10m/1e]

  1. Determine the output current of the Widlar current source; given that ±V=±15 volts, IC0=10−14 amp., β=200, VT=25 mV.

[Figure: Widlar current source: p-n-p transistor Q1 (emitter at the top, connected to the +V rail, emitter arrow pointing in) with its base and collector shorted (diode-connected); from the collector of Q1 a 39 kΩ resistor (current Iin flowing downwards) to the collector of Q2; Q2 is an n-p-n transistor with base and collector shorted (diode-connected) and its emitter connected to the −V rail; the base of Q2 is connected to the base of Q3; Q3 (n-p-n) emitter goes through a 5 kΩ resistor to −V; the collector of Q3 goes upwards (dotted line) to the load, carrying output current Io (downwards)] [2012/20m/2c]

  1. For the current mirror shown in Fig. 4 (c), determine the emitter current of transistor Q3. (Assume β=100 and VBE=0.6 V)

[Figure: Fig. 4 (c): From ground, current I flows through a 4K7 resistor to node a. Transistor Q1 (n-p-n): collector at node a (current IC1), emitter to the −10 V rail, base connected to the horizontal line just right of a (base current IB1); current I1 flows along the line from a to the base tap and I1′ onward to node b. Transistor Q2 (n-p-n): collector at node b (current IC2), emitter to −10 V, base connected to the line just right of b (base current IB2); current I2 flows from b along the line, which continues as base current IB3 into the base of Q3. Q3 (n-p-n): collector through a 4K7 resistor to +10 V (current IC3 downwards), emitter to the −10 V rail (current IE3 downwards)] [2011/20m/4c]

  1. For the voltage series feedback amplifier shown in Fig. 5, calculate Vf, feedback ratio β, voltage gain without feedback AV and voltage gain with feedback AVf:

[Figure: Fig. 5 – Source Vs in series with the amplifier input; input voltage of the amplifier block AV is 5 mV (+ at top input terminal); output Vo=2 V across a load resistor; feedback network (dashed box) of 19 K and 1 K in series across the output: 19 K from the upper output terminal to a tap, 1 K from the tap to the lower output line; the voltage across the 1 K is Vf, connected in series between the source Vs and the lower input terminal of the amplifier] [2010/6m/2b(ii)]

  1. For the class C tuned amplifier shown in the above figure, calculate the maximum load power and the transistor power rating if VCE(sat)=0.75 V.

[Figure: Class C tuned amplifier: a.c. input source (sine wave sketched beside it; + terminal up, other terminal grounded) through a series resistor and a coupling capacitor to the base of an NPN transistor; a resistor from the base to ground; emitter grounded; collector connected to a parallel LC tank (capacitor in parallel with the transformer primary) whose other end goes to the supply +60 V [?]; the primary is coupled through a 2:1 transformer to a 60 Ω load resistor on the secondary] [1999/20m/6a]

  1. For the voltage-series-feedback amplifier circuit shown in Fig. 1(d), the open-loop gain A of the OP-AMP varies from 15000 to 20000 as the temperature changes from 25°C to 35°C. Calculate the closed-loop gain at both the extreme temperatures, assuming R1=470Ω and Rf=47kΩ. Calculate the percentage change in open-loop and closed-loop gains and explain the results. Assume the source impedance to be zero.

[Figure: Fig. 1(d): Op-amp A (supplies VCC and −VEE) used as a non-inverting amplifier: source Vi connected between ground and the non-inverting input; a feedback resistor from the output to the inverting-input node (feedback voltage Vf marked); R1 from that node to ground; load RL across the output; output voltage Vo across RL] [1997/20m/1d]

4.6] Op-amp circuits and filters

43 questions

  1. For the circuit given in the figure below, the input voltage signal is given by Vin=1.5sin62.8t+0.5sin188.4t volts. Determine the output voltage expression for each input component indicating their magnitude and phases. Derive the frequency domain expression for the output voltage:

[Figure: Op-amp circuit: Vin through series capacitor C=1.0μF to the non-inverting (+) input; R1=10K from the + input node to ground. Inverting (−) input: R2=22K from the − input to ground and feedback resistor R3=10K from the output Vo to the − input. Output Vo] [2026/10m/5a]

  1. Define input bias current and input offset voltage for an OPAMP. Using an OPAMP, draw an inverting amplifier circuit with gain =−4 in such a way that the effect of bias current is minimized. [2024/10m/4b(i)]

  2. An inverting Op-Amp circuit is to be designed such that the weighted sum v0=−(v1+4v2). Resistors R1, R2 and Rf are to be chosen in a way that for a maximum output voltage of 4 V, the current in the feedback resistor does not exceed 1 mA.

[Figure: Inverting summing amplifier: input v1 through R1 and input v2 through R2 to the inverting (−) input of the op-amp; feedback resistor Rf from the output v0 to the inverting input; non-inverting (+) input grounded.]

Calculate the values of R1, R2 and Rf. [2023/10m/3c]

  1. An op-amp circuit is shown in Figure 1(d) below. Assume the op-amp to be ideal. (i) Determine I1, I2, I3 and VX. (ii) If Vo is not to be lower than – 13 V, calculate the maximum allowed value for RL. (iii) If RL is varied in the range 100 Ω to 1 kΩ, what is the corresponding change in IL and in Vo?

[Figure: Figure 1(d): Ideal op-amp, non-inverting (+) input grounded. A 1 V source (+ terminal on top, − terminal grounded) feeds the inverting (−) input through a 10 kΩ resistor carrying current I1 (arrow towards the op-amp). From the inverting-input node a wire rises to a top branch: a 10 kΩ resistor carrying current I2 (arrow to the right) to node VX. From node VX a 100 Ω resistor goes down to ground, with current I3 marked by an arrow pointing upward (from ground towards VX). From node VX a variable resistor RL carrying current IL (arrow to the right) goes to the right and down to the op-amp output terminal Vo.] [2022/10m/1d]

  1. Explain what happens when a circuit shown in Figure 3a(i) below is constructed using logarithmic amplifier.

[Figure: Figure 3(a)(i): VREF through R1 to the inverting (−) input of an op-amp; non-inverting (+) input grounded. npn transistor Q1: base grounded, collector connected by a feedback wire to the inverting input, emitter connected to the op-amp output node V1. npn transistor Q2: base connected to V1, collector current IX (arrow into the collector), emitter connected to the − terminal of a battery whose + terminal is grounded.] [2021/10m/3a(i)]

  1. Explain what happens if the topology is modified as shown in Figure 3(a)(ii) below.

[Figure: Figure 3(a)(ii): Same op-amp and Q1 arrangement as Figure 3(a)(i) (VREF through R1 to the inverting input, + input grounded; Q1 base grounded, collector to the inverting input, emitter to the output node V1). npn transistor Q2 now has its base grounded, its emitter connected to V1 and collector current IX (arrow into the collector).] [2021/10m/3a(ii)]

  1. Determine the closed loop gain of the inverting amplifier shown in Figure 4(c) below. Explain the result if R1→0 or R3→0.

[Figure: Figure 4(c): Op-amp with A0=∞, non-inverting (+) input grounded. Vin (+ terminal on top, − terminal grounded) through R2 to the inverting (−) input. T-network feedback: from the inverting input, R3 to node Vx; R4 from node Vx to ground; R1 from node Vx to the output Vout.] [2021/10m/4c]

  1. A first order low pass filter circuit is shown in Figure 4(c) below. It is desired that the dc gain of the filter be 5 and the input impedance is 10 kΩ. The value of the capacitor C = 100 nF. Find the values of R, R1 and the cut-off frequency fc of the filter. (Assume ideal OP-AMP)

[Figure: Figure 4(c): Inverting op-amp low-pass filter: input Vi through R1 to the inverting (−) input; non-inverting (+) input grounded; feedback from output Vo to the inverting input through R in parallel with C = 100 nF] [2020/10m/4c]

  1. Determine the output voltage of the op-amp differentiator circuit shown in Figure 2(c) for the triangular wave input as shown and draw the output voltage waveform.

[Figure: Figure 2(c): Input triangular wave against t: −10 V at t = 0, rising linearly to +10 V at t = 10 μs, falling linearly to −10 V at t = 20 μs, then rising again (peaks +10 V, troughs −10 V, period 20 μs). Differentiator: input through a 0.001 μF capacitor to the inverting (−) input of an op-amp; feedback resistor Rf=2.2kΩ from the output Vo to the inverting input; non-inverting (+) input grounded] [2019/10m/2c]

  1. For the op-amp circuit shown in Figure 1(d), determine the gain Av=vovi. Assume that all resistors are equal.

[Figure: Figure 1(d): Op-amp with non-inverting (+) input grounded. Input vi connected through resistor R (current i flowing towards the op-amp) to the inverting (−) input. Feedback network from the inverting input to the output vo: a chain of three series resistors R – R – R; at the junction between the first and second R a resistor R goes to ground, and at the junction between the second and third R another resistor R goes to ground; the third R connects to the output vo. All resistors are R] [2018/10m/1d]

  1. The integrator circuit shown in Figure 4(c) is to be used to generate a triangular waveform from a 500 Hz square wave connected to its input. Suppose that the square wave alternates between ± 12 V. (i) Find the minimum slew rate required for the amplifier. (ii) Find the maximum output voltage the amplifier can generate.

[Figure: Figure 4(c): Op-amp integrator: square-wave input applied through a 400 Ω resistor to the inverting (−) input; feedback from output vo to the inverting input is a 4.7 kΩ resistor in parallel with a 1 μF capacitor; the non-inverting (+) input is connected to ground through a 370 Ω resistor; output terminal vo] [2018/10m/4c]

  1. Calculate the output voltage vo in terms of the input voltages vi1, vi2, vi3 and vi4 for the circuit shown in Figure 8(b).

[Figure: Figure 8(b): Op-amp summing (difference) amplifier. Input vi1 through R1 and input vi2 through R2 join at the inverting (−) input; feedback resistor RF from the output vo to the inverting input. Input vi3 through RA and input vi4 through RB join at the non-inverting (+) input, which is connected to ground through RC. Output terminal vo] [2018/20m/8b]

  1. For the circuit given in Fig. 1(d)– (i) draw the input and output waveforms; (ii) find the average value of the output voltage waveform. Assume that the diode in the circuit is ideal.

[Figure: Fig. 1(d): Op-amp supplied from +15 V and −15 V, output Vo. AC source v(s)=sinωt, ω=2*50*π: its upper terminal connects through a 660 Ω resistor to the non-inverting (+) input; its lower terminal is connected to ground. From the ground node a 1 kΩ resistor in series with a diode (anode towards the 1 kΩ resistor, cathode towards the op-amp) connects to the inverting (−) input; a 2 kΩ feedback resistor connects the inverting input to the output Vo] [2017/10m/1d]

  1. (i) Draw the circuit diagram of a bandpass filter using OP-AMP. Its parameters are fL=300 Hz, fH=2 kHz and passband gain is 4. (ii) Calculate the value of Q. Assume that the capacitor value is 0.01μF. [2017/20m/8b]

  2. For the circuit shown in Fig. 3(c), get the expression for Vo. Also sketch the output waveform. Assume that the op-amp is ideal. R=LC, ω=1LC and Vi=10sinωt:

[Figure: Fig. 3(c): Inverting op-amp circuit: input Vi → resistor R in series with capacitor C → inverting (−) input; feedback path from output Vo to the inverting input consisting of inductor L in series with resistor R; non-inverting (+) input grounded] [2016/10m/3c]

  1. For the op-amp circuit shown in Fig. 4(c), deduce the output voltage expression. Calculate Vo, when R1=1kΩ=R2, R3=1K and R4=2K and Vin=1V:

[Figure: Fig. 4(c): Op-amp circuit: input Vin drives two branches: R1 to the inverting (−) input and R2 to the non-inverting (+) input; R3 from the non-inverting input to ground; feedback resistor R4 from the output Vo to the inverting input] [2016/10m/4c]

  1. In the Figure shown what is the function of R0 and determine its value when V0=−3V1−2V2.

[Figure: Op-amp summing amplifier: input V1 through R1 and input V2 through R2 to the inverting (−) input; feedback resistor 6 kΩ from the output V0 to the inverting input; non-inverting (+) input connected through R0 to the common bottom line, which runs between two open terminals (no ground symbol drawn)] [2015/10m/1d]

  1. (i) Why the output voltage of an Op-Amp does not respond immediately to the fast-changing input? (ii) Develop the expression for the slew rate of Op-Amp. (iii) An open-loop configuration of Op-Amp 741C changes its output from +14 V to –14 V each time its input crosses zero volt. If 741C has a typical slew rate of 0.5V/μs, calculate the time between the zero crossings and the maximum frequency at which the output will be distorted. [2014/20m/4a]

  2. Design an amplifier with a gain of +5 using one OP-AMP. Choose Ri=10kΩ. [2013/10m/1d]

  3. Define the following parameters for an OP-AMP: Input offset voltage; Bias current; Slew rate; Output impedance; CMRR. [2013/5m/1e(ii)]

  4. Using an OP-AMP, design a lossy integrator whose peak gain is 20 dB and the gain is 3 dB down from its peak when ω=10000 rad/sec. Use a capacitance of 0.01 μF. [2013/20m/4a]

  5. Design a second-order low-pass Butterworth filter having a cutoff frequency of 1 kHz. Choose C=0.1μF. The damping factor α is given to be 1.414. Choose Ri as 10 kΩ. [2013/20m/4c]

  6. Assuming ideal op-amps, determine the expression for the input impedance of the given circuit and a simple passive equivalent of the circuit looking into terminal ①.

[Figure: Terminal ① (+) and a lower return terminal (−) with Vin between them and input current iin flowing into terminal ①. Terminal ① is connected to the non-inverting (+) input of op-amp 1, whose inverting (−) input is tied to its own output (voltage follower). The output of op-amp 1 goes through capacitor Co to a node X; resistor R1 is connected from X to the lower (−) terminal line. Node X is connected to the non-inverting (+) input of op-amp 2, whose inverting (−) input is tied to its own output (voltage follower). Resistor R2 is connected between terminal ① (input line) and the output of op-amp 2] [2012/12m/1e]

  1. Draw the circuit of an opamp integrator. Sketch the output waveform, when the input is a symmetrical square wave of amplitude ±3 V and the repetition frequency is 1 kHz. [2010/4m/5b(i)]

  2. Design an opamp second-order Butterworth low-pass filter (LPF) for a cut-off frequency of 2 kHz. Compare the response curve with that of first-order LPF. [2010/10m/6b(i)]

  3. With OP-AMP draw a circuit of a unity gain amplifier having no phase shift and give its one practical application. [2007/5m/8a(ii)]

  4. Draw the circuit of a two input adder with OP-AMP and explain its operation. [2007/5m/8a(iii)]

  5. The ideal op-amp circuit of the figure given below converts voltage vi into a current iL. Show that if 2R1=2R2=R3+R4 and R4−R1=500Ω then iL=+vi mA.

[Figure: Op-amp: input vi through R1 to the inverting (−) input; R2 from the output vo to the inverting input; R3 from the output vo to the non-inverting (+) input; R4 from the non-inverting input to ground, carrying the load current iL (downwards) with voltage vL across it (+ at top)] [2006/10m/3a(iii)]

  1. Design a second-order active RC band-pass filter with a mid-band voltage gain −A0=34 dB, carrier frequency 160 Hz and 3 dB bandwidth 16 Hz. Assume C1=C2=0.1μF. [2005/10m/1b(ii)]

  2. The 741C op-amp having the following parameters is connected as shown in the figure. A = 20000, Ri=2MΩ, R0=75Ω, f0=5 Hz, supply voltage = ±15 V, output voltage swing ±13 V. Identify the circuit. Compute the values of AF, RIF, ROF, fF & VOUT

[Figure: 741C op-amp with supplies VCC and VEE; input source vin between the non-inverting (+) input and ground; 1 kΩ resistor from the inverting (−) input to ground and 10 kΩ feedback resistor from the output to the inverting input; load RL from the output vo to ground.] [2005/10m/5b(i)]

  1. Draw the circuit diagram of voltage-to-current converter with floating load using op-amp. Derive the necessary equation. [2005/5m/8a(iii)]

  2. Design a second-order Butterworth low-pass filter with cut off frequency of 1 kHz [?]. Use only Sallen and Key network configuration as shown below:

[Figure: Sallen–Key low-pass filter: Vin through resistor R to node A; from A a second resistor R to the non-inverting (+) input of the op-amp; capacitor C from the + input to ground; a second capacitor C from node A to the op-amp output (feedback); resistor R1 from the inverting (−) input to ground and resistor R2 from the output to the inverting input; output Vout.] [2004/8m/6a(i)]

  1. The following two amplifier circuit is a generalized immitance converter (GIC). Analyze the above circuit to get an expression for Zin. Assume the two op-amps to be ideal.

[Figure: Five impedances: Z1, Z2, Z3, Z4 connected in series in a horizontal chain starting at the upper input terminal (nodes: input node, node A between Z1 and Z2, node B between Z2 and Z3, node C between Z3 and Z4, node D after Z4); Z5 from node D down to the lower input terminal (bottom wire). Op-amp OA1 (drawn above the chain): + input to the input node, − input to node B, output to node C. Op-amp OA2 (drawn below the chain): − input to node B, + input to node D, output to node A. Zin is the impedance looking into the two input terminals (arrow).] [2003/10m/2a(i)]

  1. With Z1=R1, Z3=R3, Z2=1/C2s, Z4=R4 and Z5=R5, what does the GIC circuit above realize? [2003/2m/2a(ii)]

  2. Z1 and Z5 are capacitors, Z2, Z3 and Z4 are resistors. How does the input impedance Zin, behave? [2003/2m/2a(iii)]

  3. Consider the op-amp circuit shown.

[Figure: Op-amp circuit: input vi through resistor R1 to the inverting (−) input; feedback resistor R2 from the inverting (−) input node to the output vo; the non-inverting (+) input connected to ground through an unlabelled resistor.]

In the circuit make the usual assumption that (i) the inverting and non-inverting terminals are virtually at the same potential and (ii) the op – amp does not take any input current at its terminals. You would arrive at the normal conclusion that v0=−viR1.R2. Is this conclusion valid? If yes give reasons why operational amplifiers are never used in this manner with inverting input grounded and input to be amplified given to the non-inverting terminal. [2002/20m/5a]

  1. The above figure shows the circuit of a voltage follower. Calculate its closed loop voltage gain, input impedance and output impedance. Determine also the output offset voltage. The parameters of 741 C are: Open loop gain AOL=105, rin=2MΩ, rout=75Ω, Vin(off) 2mV, Iin (bias) = 80 nA and Iin(off) = 20 nA.

[Figure: Voltage follower using a 741 C op-amp: a.c. signal source (+ terminal up, other terminal grounded) connected through a 33 KΩ resistor to the non-inverting input; output VOUT connected directly back to the inverting input] [1999/20m/5a]

  1. Select any three of the following statements, read them carefully and identify correct and incorrect ones. Justify your answer using not more than 200 words in each case: An operation amplifier has features suitable for radio frequency timers. [1999/20m/200w/1d]

  2. Select any three of the following statements and indicate with justification whether they are correct or incorrect. Your answer must not exceed 200 words for each statements: The characteristic of a twin–T network is similar to that of a notch filter in audio frequency range. [1999/20m/200w/9a]

  3. Find the output voltage in steady state condition for the operational amplifier shown in the figure below when (i) switch S is open, (ii) switch S is closed.

[Figure: Inverting op-amp circuit: input Vi through a resistor R to the inverting (−) input; non-inverting (+) input grounded; feedback network from the inverting input: a resistor R to an intermediate node, and from that node to the output Vo two parallel paths – a resistor R, and a switch S in series with a capacitor C] [1998/20m/1b]

  1. Explain the working of a timer using general purpose OP AMP IC 741. Design such a timer for a time period of 60 seconds. [1998/20m/4a]

  2. Explain the following terms as referred to an operational amplifier: (a) Input offset voltage and (b) Input offset current. [1996/10m/5d(i)]

  3. Find the relation between vo and vs for the circuit of Fig. 8a and show that, with proper adjustments, the voltage v0 can be made proportional to the logarithm of the input voltage vs.

[Figure: Fig. 8a: Input vs (+) applied through a resistor to the inverting input of op-amp A1, whose non-inverting input is grounded; transistor Q1 (base grounded) in the feedback path of A1, its collector joined to the inverting input and its emitter joined (dashed line) to the node after resistor R, which is in series with the output of A1; this node also goes to the emitter of transistor Q2; the collector of Q2 is connected through R2 [?] to VR and, together with the base lead of Q2 [?], to the non-inverting (+) input of op-amp A2; A2 is a non-inverting amplifier with R4 from its output to its inverting input and R3 from the inverting input to ground; output vo (wiring around Q2 partly unclear in the source)] [1996/20m/8a]

4.7] Oscillators and wave-shaping circuits

17 questions

  1. Consider the circuit of an operational amplifier given here in which Zener diodes Z1 and Z2 are having reverse breakdown voltage = 7.4 V and forward voltage drop = 0.6 V. (i) Draw the output voltage waveform showing voltage value with time and calculate frequency of output waveform. (ii) Modify the circuit for duty cycle factor D=0.25 by replacing R1 from combination of suitable resistances and diodes, so that output frequency is not changed.

[Figure: Op-amp astable circuit, supplies +12 V and −12 V. Inverting (−) input at node V1; capacitor C1=0.1μF from V1 to ground. Op-amp output through R2=1K to node V3 (OUTPUT). Feedback resistor R1=100K from V3 back to V1. Potential divider from V3 to ground: R3=39K from V3 to node V2 and R4=1K from V2 to ground; V2 is connected to the non-inverting (+) input. Two Zener diodes Z1 and Z2 in series back-to-back from V3 to ground (Z1 cathode at V3, Z2 cathode at ground, anodes joined)] [2025/20m/2b]

  1. Explain the working of the given OPAMP circuit. Draw the output waveforms at points A and B showing the time and voltage. Given that, VZ1=VZ2=3.3V, C1=1μF, the power supply voltage to OPAMPs is ±12 V and R1=R2=R3=R4=R5=R6=2kΩ:

[Figure: Three op-amps I1, I2, I3. I1: inverting (−) input grounded; non-inverting (+) input at a node F. Output of I1 through R3 to node D. From D to ground: two Zener diodes Z1 and Z2 in series, back to back. R2 from D back to node F. From D, R4 to the inverting input of I2; capacitor C1 from the inverting input of I2 to its output; non-inverting input of I2 grounded; output of I2 is point A. R1 from output A back to node F. Node D is also connected to the non-inverting (+) input of I3; output of I3 is point B; R6 is connected between the inverting (−) input of I3 and a node joined to output B, and R5 from that node to ground.]

Suggest to replace suitable resistances so that the output voltages at A and B are having swing of ±6 V and the output frequency is fixed to 500 Hz. [2024/20m/3b]

  1. Determine the feedback fraction and the operating frequency for the oscillator circuit shown in Figure 6(c).

[Figure: Figure 6(c): Colpitts-type oscillator with an NPN transistor, emitter grounded. Collector connected to VCC through RFC = 100 μH. Base bias: RB1 from VCC to base, RB2 from base to ground. Collector node connected to: the top of inductor L1=1μH; the top of capacitor C2=10pF; and, through coupling capacitor CC=100pF, to the output vo. The lower end of C2 and the upper end of C1=100pF join at a node connected to ground; the lower end of C1 and the lower end of L1 join and are connected by a wire back through a second coupling capacitor CC=100pF to the base] [2018/10m/6c]

  1. Find the average voltage at the point Vo in the circuit given in Fig. 4(c):

[Figure: Fig. 4(c): Op-amp supplied from +15 V and −15 V, output Vo. Source v(t)=5sinωt, ω=2*π*50, with its lower terminal grounded; its upper terminal connects through a 1 kΩ resistor to the inverting (−) input. The non-inverting (+) input is connected to a node that goes to ground through a Zener diode (cathode at the node, anode at ground) and to the output Vo through a 1 kΩ feedback resistor. Zener data: VZ=2.5 V (Zener voltage), VFZ=0 V (Forward voltage drop)] [2017/10m/4c]

  1. (i) Draw the circuit diagram of Wien bridge oscillator using OP-AMP. (ii) Find the value of R to get a sustained oscillation of 1115 Hz. Assume that the value of the capacitor is 0.1μF. [2017/10m/6c]

  2. Figure shows a sinusoidal oscillator. By an appropriate analysis, determine the condition of oscillation and frequency of oscillation in terms of circuit elements assuming ideal op-amps.

[Figure: Three op-amp stages in cascade with an overall feedback loop. Stage 1: from the input node Ro to the inverting (−) input and C1 to the non-inverting (+) input; R1 from the (+) input to ground; feedback resistor Ro from the output to the (−) input. Stage 2 (fed from stage 1 output): identical with Ro (input to −), C2 (input to +), R2 from (+) to ground and feedback Ro. Stage 3: inverting amplifier with input resistor R3 from stage 2 output to the (−) input, feedback resistor R4 from output to (−) input, (+) input grounded; its output is Vo, which is also fed back by a wire to the input node of stage 1] [2012/20m/3c]

  1. Explain the operation of the given circuit by sketching relevant waveforms assuming that positive and negative saturation levels of output voltage of the op-amp comparator are +Vsat1 and −Vsat2 respectively and are not equal. Determine an expression for the frequency of the generated output voltage.

[Figure: Op-amp (supplies +V and −V′) astable circuit: resistor R from the output Vo to the inverting (−) input; capacitor C from the (−) input to ground; resistor Rb from the output to the non-inverting (+) input; resistor Ra from the (+) input to ground] [2012/20m/4c]

  1. Using an OP-AMP, several capacitors of 0.1 μF and number of resistances of your choice, design a phase-shift oscillator to oscillate at 100 Hz. [2011/20m/4a]

  2. Using an opamp and RC network, explain the working of a Wien bridge oscillator. For a frequency of 1 kHz, design a Wien bridge oscillator. [2010/10m/7a(i)]

  3. Derive the condition of oscillation and the expression for the frequency of oscillations for the circuit shown. (Use mesh analysis and Barkhausen’s criteria). Draw actual oscillator circuit with one operational amplifier and minimum number of RC elements.

[Figure: RC phase-shift network: three equal capacitors C in series along a horizontal line from the left node V0 to the right terminal V; resistor R from the left node V0, from the junction of the first and second capacitors and from the junction of the second and third capacitors to a common bottom line, which is grounded; an amplifier block A drawn above the network, with a wire rising from the left node V0 and a wire rising from the right terminal V towards it (connections to the amplifier not completely drawn)] [2007/15m/4a(i)]

  1. Explain with the help of neat diagram, the operation of a Schmitt trigger employing OP-AMP. [2007/10m/8a(i)]

  2. Discuss the criteria for a circuit to oscillate. Explain the operation of a phase shift oscillator and derive an expression for the frequency of oscillation of an RC phase shift oscillator. [2003/20m/6a]

  3. Obtain the conditions under which the circuit below produced oscillations.

[Figure: Op-amp Wien-bridge oscillator. The op-amp output (terminal of vo, measured with respect to the bottom ground wire) is connected to a top wire. From the top wire: (1) resistor R in series with capacitor C down to node P; node P connected to the non-inverting (+) input; resistor R and capacitor C in parallel from node P to the bottom (ground) wire; (2) resistor R1 from the top wire down to node Q; node Q connected to the inverting (−) input; resistor R2 from node Q to the ground wire. vo is taken between the output and ground.]

What is the frequency of oscillations? [2002/20m/4a]

  1. The simplified circuit of a radio oscillator is shown in Fig. above. Draw its equivalent circuit and obtain the condition of oscillation. Obtain the frequency of oscillation and the value of hfe required for the oscillation in the case of Hartley oscillator.

[Figure (printed above the text): Transistor oscillator (common emitter, emitter grounded). Impedance Z1 between the top wire (connected to the collector) and the base; impedance Z3 [?] between the base and the bottom (ground) wire; impedance Z2 [?] between the top (collector) wire and the bottom (ground) wire on the right. Subscripts of the two lower/right boxes are blurred.] [2001/20m/6b]

  1. Explain the operation of colpitts oscillator. A colpitts oscillator has a tank circuit as shown in the above figure. Calculate its frequency of oscillation. What should be the minimum gain of the amplifier for the oscillations to start?

[Figure: Colpitts tank circuit: two capacitors in series, 0.001 μF (upper) and 0.01 μF (lower), connected in parallel with a 12 μH inductor; the junction of the two capacitors is brought out through a capacitor to the (grounded) common terminal] [1999/20m/8b]

  1. Draw the circuit diagram of an R-C phase shift oscillator using a transistor with CE configuration and derive an expression for its frequency of oscillation. Prove that Hfe=23+29RRL+4RLR1 [1998/20m/7c]

  2. The input vi(t) in the circuit of Fig. 5d is vi(t)=1.5sin2π×103t volt with t in sec, Sketch v0(t) and label important points.

[Figure: Fig. 5d: Op-amp; source vi(t) connected between the upper input terminal of the op-amp and ground; the lower input terminal is connected to ground through a 1 kΩ resistor and to the output through a 3 kΩ resistor; output vo(t) taken with respect to ground (input polarity marks on the op-amp not legible; the arrangement is a regenerative comparator)] [1996/10m/5d(ii)]

4.8] Power supplies

3 questions

  1. In the linear regulated power supply circuit shown here, calculate the output voltage adjustment range and maximum power dissipation in transistor T1 in worst case:

[Figure: Input 15 V to 20 V DC between the top rail and the grounded bottom rail. 1 kΩ from the input rail to node Z; 12 V Zener diode (+ at top) from Z to ground. Across the Zener (from Z to ground): 1 kΩ, a 10 kΩ potentiometer and 1 kΩ in series; the potentiometer wiper goes to the non-inverting (+) input of op-amp I1. Op-amp I1 is supplied from the input rail and ground. Output of I1 through 470 Ω to the base of T1; collector of T1 to the input rail; emitter of T1 through 0.7 Ω to the output terminal. Transistor T2: base at the emitter of T1 (top of the 0.7 Ω), emitter at the output end of the 0.7 Ω, collector at the base of T1. The inverting (−) input of I1 is connected to the output terminal. Output taken between this terminal and the grounded rail.]

(T1 and T2 are Si transistors) [2024/10m/4b(ii)]

  1. Design a voltage regulator using 7805 IC to get a voltage output of 8 V. [2013/10m/4b]

  2. A simple voltage regulator circuit is shown in Fig 4(c). The zener voltage is given by Vz=(10+0.20iz) volts where iz is in mA. For a given transistor, assume β=100 and VBE=0.3 V (constant). Determine % load regulation if maximum load current of 500 mA is switched off.

[Figure: fig.4 (c): Series (emitter-follower) regulator: 20 V d.c. input between the + and − input terminals; NPN transistor (β=100, VBE=0.3 V) with collector to the + input line and emitter to the load (load current 500 mA); 500 Ω resistor from the + input line to the base; zener diode (Vz) from the base to the − line (cathode at the base); the load block connected between the emitter and the − line] [1998/20m/4c]

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