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Circuits—Theory – Electrical Engineering Optional PYQs (1995–2026)

Here are all 144 Circuits—Theory questions asked in UPSC Electrical Engineering Optional Paper I from 1995 to 2026, arranged under the 8 topics of the official syllabus. Within each topic the latest questions come first.

Each question ends with a code such as [2024/15m/3b] – the year, the marks, the word limit (where UPSC set one) and the question number in the paper.

Topic-wise weightage graph of Circuits—Theory, Electrical Engineering Optional Paper I, 2013–2026 vs 2022–2026
Topic-wise weightage of Circuits—Theory (Paper I) – share of marks, 2013–2026 (white) vs 2022–2026 (black).

1.1] Circuit elements, network graphs, KCL and KVL

13 questions

  1. For the circuit shown in Figure 1(a), find the Vin, Vs and power supplied by the dependent source.

[Figure: Figure 1(a): Circuit with a common bottom (return) wire. Left branch: independent voltage source Vin, + terminal at top, connected between the bottom wire and the top-left node. Top-left wire carries current 2 A (arrow pointing right) through a 5 Ω resistor and then a 60 V independent voltage source (− terminal on the left, + terminal on the right) to the top middle node. Middle branch from the top middle node down to the bottom wire: current ix (arrow pointing down) through a 3 Ω resistor in series with a battery Vs (− terminal on top, + terminal at the bottom). From the top middle node a 2 Ω resistor goes right to the top-right node; current 8 A is marked on this wire with the arrow pointing left (from the top-right node towards the 2 Ω resistor). Right branch from the top-right node down to the bottom wire: dependent (diamond) voltage source 4ix, + terminal at top.] [2022/10m/1a]

  1. The reduced incidence matrix of an oriented graph is given as [0−110000−1−1−1−10001] (i) Draw the graph. (ii) How many trees are possible for this graph? (iii) Write the tie-set matrix. [2016/10m/1a]

  2. Find the values of E and I in the circuit shown in Fig. 1.

[Figure: Fig. 1 – Ladder network. Voltage source E on the left (+ terminal at top) between the top rail and the bottom (return) rail; current I flows from the + terminal of E to the right through a series 2 Ω resistor along the top rail to node 1. From node 1 a 6 Ω resistor goes down to the bottom rail; a second series 2 Ω resistor goes along the top rail from node 1 to node 2. From node 2 a 4 Ω resistor goes down to the bottom rail carrying a marked current of 2 A (arrow pointing downward through the 4 Ω); a 2 Ω resistor from node 2 to the bottom rail is in parallel with the 4 Ω (rightmost branch).] [2014/10m/1a]

  1. A storage battery has a no-load terminal voltage of 6 V. When the current through the battery is 100 A, the terminal voltage drops to 5 V. Show a pictorial representation of the battery as a constant current source. [2011/15m/1a]

  2. The current i(t)=2t0≤t≤1;=−2t+41≤t≤2;=0otherwise is passed through a capacitor of 0.5 farad. Find the expression for the voltage across the capacitor in the time interval 1≤t≤2. [2009/5m/1a(i)]

  3. For the circuit given below draw the network graph and draw any three possible trees of the network. Prove that for the network graph L = B − (N − 1) where L = no. of links B = no. of branches N = no. of nodes.

[Figure: Triangular network with an internal star: outer vertices T (top), BL (bottom left) and BR (bottom right) and a central node O; side T–BL: 10 Ω in series with a 10 V source (polarity marks not clearly legible); side T–BR: 10 Ω; side BL–BR: 10 Ω; 5 Ω from each of T, BL and BR to the central node O] [2006/5m/3a(i)]

  1. Define the following terms related to electrical circuits An ideal filter SPICE Network graph d. [2006/5m/8a(i)]

  2. For the circuit shown below, find i1, i2, i3 and i4.

[Figure: Circuit drawn as a horizontal chain of elements between six nodes A–F from left to right: 25 Ω resistor from A to B, with voltage V1 across it (+ at A); a dependent (diamond) current source 0.2V1 from B to C, arrow pointing towards C; 10 Ω resistor from C to D; independent 25 A current source from D to E, arrow pointing towards D (leftwards); 100 Ω resistor from E to F. Four curved wires short pairs of nodes: an upper arc from A to C carrying current i1 (arrow left to right), an upper arc from C to E carrying i2 (arrow left to right), a lower arc from B to D carrying i3 (arrow left to right) and a lower arc from D to F carrying i4 (arrow left to right).] [2005/5m/1a(ii)]

  1. What is cut-set in linear graph theory? Explain with an example. In the graph.

[Figure: Oriented graph with nodes ① (left), ② (middle of the top horizontal line), ⑤ (right) and ④ (bottom, also marked 0). Branches: 3 – upper arc from node 1 to node 5 (arrow towards 5); 2 – from node 1 to node 2 (arrow towards 2); 4 – from node 5 to node 2 (arrow towards 2); 6 – vertical, from node 2 down to node 4 (arrow downwards); 1 – between node 4 and node 1, arrow pointing towards node 1; 5 – between node 4 and node 5, arrow towards node 5 [?].]

check if the sets of branches {1, 3, 4, 6} {1, 2, 3}, {1, 2, 3, 5} constitute cut-sets. [2001/20m/7a]

  1. A non-sinusoidal current i(t) as shown in the above figure is passed through a capacitance C = 100 μF. Determine the voltage across the capacitance when ω = 1000 rad/sec.

[Figure (printed above the text): Waveform of i(t) against θ = ωt: triangular wave starting at +I at θ = 0, falling linearly through zero at π/2 to −I at π, then rising linearly through zero at 3π/2 to +I at 2π.] [2000/20m/5a]

  1. Determine the resistance across the terminals A and B of the network shown in the above figure.

[Figure: Twelve 10 Ω resistors forming the edges of a cube, drawn as two nested rhombuses: outer rhombus with corners L (left), T (top), B (right, terminal B) and D (bottom), edges L–T, T–B, L–D, D–B each 10 Ω; inner rhombus with corners A (left, terminal A), T′ (top), R′ (right) and D′ (bottom), edges A–T′, T′–R′, A–D′, D′–R′ each 10 Ω; four connecting resistors L–A, T–T′, R′–B and D–D′, each 10 Ω. Terminals A and B are diagonally opposite corners of the cube] [1999/20m/4c]

  1. Fig. 1 (a) shows a network of resistors each of R ohms. Find the resistance between the terminals P and Q.

[Figure: Fig. 1 (a): Triangle of corners A (top), B (bottom left) and Q (bottom right) with a resistor R in each side (A–B, A–Q, B–Q); an inner node P inside the triangle connected to A through a vertical resistor R and to B through a resistor R; terminal P (small circle) is taken from the inner node and terminal Q (small circle) is joined by a wire to corner Q] [1997/20m/1a]

  1. Fig. Q. 1(b) shows the details of a portion of a d.c. network. Evaluate the voltage V.

[Figure: Fig. Q 1(b): Two networks N1 (top) and N2 (bottom) joined by two vertical wires: in the left wire a current of 3 A flows downwards (from N1 to N2), in the right wire a current of 2 A flows upwards (from N2 to N1). A third terminal of N1 is connected by the top line to the top corner of a bridge, and a third terminal of N2 by the bottom line to the bottom corner of the bridge; the voltage between the top and bottom lines is marked Vx [?] (+ at the top line). Bridge (diamond) arms: top corner to left corner 1 Ω; top corner to right corner 3 Ω; left corner to bottom corner 1 Ω; right corner to bottom corner 1 Ω [?]; between the left and right corners a 1 Ω [?] resistor in series with a 4 V battery (polarity not legible)] [1995/20m/1b]

1.2] Nodal and mesh analysis

15 questions

  1. For the circuit shown below, if the power loss in 1Ω resistor is 16 W, find the value of k in the dependent source using nodal method:

[Figure: Circuit with a bottom reference (ground) rail. Left branch: 10 A independent current source, arrow pointing up, from the bottom rail to node VA. Node VA: 2Ω resistor from VA down to the bottom rail, carrying current i0 marked downward (from VA into the 2Ω). From VA to the right: 1Ω resistor in series with a dependent (diamond) voltage source ki0 (− terminal on the 1Ω side, + terminal on the VB side) to node VB. Node VB: 5Ω resistor from VB to the bottom rail; 20 V independent voltage source from VB to the bottom rail, + terminal at the top (VB)] [2026/10m/1a]

  1. For the circuit shown below, find the value of R, if the power supplied by both the sources is equal:

[Figure: Ladder circuit with a common bottom rail. Left: 100 V independent voltage source, + terminal at top, from the bottom rail to the top-left node. 5Ω resistor from the top-left node to node 1; 10Ω resistor from node 1 to the bottom rail; 20Ω resistor from node 1 to node 2; resistor R from node 2 to the bottom rail; 10 A independent current source, arrow pointing up, from the bottom rail to node 2 (right-most branch)] [2026/10m/2a(ii)]

  1. In the circuit given below, find the voltages at point A and point B.

[Figure: Triangular network with ground node G at the bottom. Top branch: A – 12Ω – node N – 6Ω – node R; a 3 A current source is connected between N and R in parallel with the 6Ω (drawn above it, arrow pointing left, i.e. from R towards N); node R is joined to node B by a wire. Node A is wired directly to an inner node P, and node B is wired directly to an inner node Q; a 9Ω resistor joins P and Q. A 3Ω resistor from P and a 4Ω resistor from Q meet at an inner node M, which is wired directly to G. Left outer branch: from A, a 6 V source (+ terminal towards A, − towards G) in series with a 6Ω resistor down to G. Right outer branch: from B, a 4Ω resistor in series with a 12 V source (− terminal towards B, + terminal towards G) down to G. G is grounded] [2025/10m/1a]

  1. Find the voltage on points A and B of the given circuit:

[Figure: Circuit with a common bottom (ground) rail. Left: 10 V source (+ at top) from ground to the top-left node. 2 Ω from the top-left node to node A (current arrow marked at A pointing down). 2 Ω from node A to ground. 1 Ω from node A to a node P; a 2 A current source from P to node Q, arrow pointing right (towards Q). 5 V source (+ at top) from node Q to ground. From node Q the top wire continues to the right-hand branch: 2 Ω and 3 Ω in series from the top rail down to ground, with terminal B at their junction (2 Ω above B, 3 Ω below B).] [2024/10m/1a]

  1. In the circuit given here, find the value of voltage v1:

[Figure: Two sub-circuits sharing a common bottom rail. Left part (its own top node): 12 mA current source (arrow up, into the top node); dependent current source vx20 (diamond, arrow up); 2 kΩ resistor carrying v1 (+ at top); 2 mA current source (arrow down, from top node to bottom rail) — all four in parallel between the left top node and the bottom rail. Right part (separate top node M): 1 kΩ resistor with voltage vx (+ at top) from M to the bottom rail; current source −5 mA (arrow up) from the bottom rail into M; 4 kΩ from M to node X; 5 V voltage source (+ at top) from X to the bottom rail; from X a 1 kΩ resistor in series with a 2 mA current source (arrow up, towards X) down to the bottom rail.] [2024/10m/2c]

  1. For the circuit shown in the figure, obtain the value of voltage across 0.5 Ω and 2.5 Ω resistors using nodal current analysis.

[Figure: Diamond-shaped network with outer nodes V3 (top), V2 (left), V4 (right), V1 (bottom) and a central node that is grounded (reference). Outer branches: 0.5 Ω between V2 and V3, with voltage Vx across it (+ at the V3 end, − at the V2 end); 2 Ω between V3 and V4; 2.5 Ω between V2 and V1, with voltage Vy across it (+ at the V1 end, − at the V2 end); dependent voltage source 0.2Vy between V1 and V4 (+ at the V4 end). Branches to the central (ground) node: 12 V source from V2 (− terminal at V2, + terminal at the centre); 2 A current source from the centre to V3 (arrow up towards V3); 1 Ω from the centre to V1; dependent current source 0.5Vx from the centre to V4 (arrow towards V4). (In the scan the + signs of Vx, Vy and 0.2Vy are printed like “×”.)] [2023/20m/2a]

  1. Find the values of branch currents Ia, Ib and Ic as indicated in the circuit of Figure 5(e).

[Figure: Figure 5(e): Current source 10.6∠0∘A (arrow upward) between the bottom wire and the top-left node; 10 Ω resistor from the top-left node to the bottom wire carrying Ia downward; from the top-left node, 1 Ω resistor in series with j2Ω (current Ix flowing to the right) to the middle node; capacitor −j5Ω from the middle node to the bottom wire carrying Ic downward; from the middle node a 5 Ω resistor (current Ib to the right) to the + terminal of a dependent voltage source 20Ix (+ at top) whose other terminal is on the bottom wire] [2020/10m/5e]

  1. In the circuit shown in Figure 3(c), find the voltage vo across the 8 Ω resistor.

[Figure: Figure 3(c): Ladder circuit between a top rail and a common bottom rail. From left: 4 Ω resistor from top-left node to bottom; 3 A current source from the same top-left node to bottom, arrow pointing downwards (current flows from the top node down into the bottom rail); 2 Ω resistor in the top rail from the top-left node to the middle node; 8 Ω resistor from the middle node to bottom, voltage vo across it with + at the top (middle node) and − at the bottom; 3 Ω resistor in the top rail from the middle node to the right branch; right branch is a 12 V battery to the bottom rail, positive (long) plate at the top] [2018/10m/3c]

  1. For the circuit shown in Fig. 2(a), find the value of V, if the power dissipation in the load resistance RL is 36 watts:

[Figure: Fig. 2(a): Two sections sharing a common bottom (reference) rail and joined only through that rail. Left section: d.c. source V (battery, longer plate/+ at top) from the bottom rail up to the top wire; a 5 Ω resistor in the top wire with voltage V1 marked across it (+ on the source side, − on the far side); beyond it a 2 Ω resistor and a 4 Ω resistor, each connected from the top wire to the bottom rail (in parallel). Right section: dependent current source 2V1 (arrow pointing up) from the bottom rail to node P at the top; 10 Ω resistor in the top wire from P to node Q; 2 Ω resistor from Q to the bottom rail; 5 Ω resistor in the top wire from Q to node S; load RL=4Ω from S to the bottom rail] [2016/20m/2a]

  1. Determine the current I in Fig. 4 using the ladder method.

[Figure: Fig. 4 – Ladder network. Source Vg = 10 V (arrow up, + at top) on the left; top wire from the source through 2 Ω to node a; bottom wire from the source directly to node a′. 200 Ω between a and a′. Top series 1 Ω from a to b; bottom series 1 Ω from a′ to b′. 50 Ω between b and b′. Top series 2 Ω from b to c; bottom wire b′ to c′ (no element). 100 Ω between c and c′. From c a series 1 Ω along the top, then down through 10 Ω (current I downward) to the bottom wire at c′.] [2013/20m/2b]

  1. Write the node equations for the network shown in Fig. 11. Assume node ② as a reference node:

[Figure: Fig. 11 – Nodes ① and ② on the top line and node ③ the bottom line. Left: source 50∠0 (+ at top) from node ③ through a 5 Ω resistor to node ①; inductor j2 from node ① to node ③; 4 Ω resistor between nodes ① and ②; capacitor −j2 from node ② to node ③; 2 Ω resistor from node ② to the + terminal of source 50∠90∘, whose other terminal goes to node ③] [2010/10m/8a(ii)]

  1. For the circuit shown below, determine the numerical value of i1, using nodal analysis.

[Figure: Ground at the bottom line. Node A (top left): connected to ground through 0.5 Ω in series with a 2 V source (+ towards node A). Current i1 flows from node A to node B through 1 Ω. Node B: 0.5 Ω to ground, and a 1 A current source from ground into node B (arrow upwards). Node B to node C through 1 Ω. Node A to node C directly through 2 Ω (top wire). Node C: 1 Ω to ground, and a 2 V source to ground (+ towards node C)] [2009/12m/4a(i)]

  1. Determine the power delivered by 6 A source.

[Figure: Bridge network between a left node and a right node: upper branch 1 Ω (left) and 2 Ω (right) in series, meeting at an upper middle node; lower branch 4 Ω (left) and 3 Ω (right) in series, meeting at a lower middle node; a 5 V source connected between the upper middle node (+) and the lower middle node (−); an outer loop connects the left node and the right node through a current source marked 6 A (drawn in the bottom wire, arrow pointing right, i.e. towards the right node)] [2007/10m/1a(i)]

  1. For the circuit shown in the figure determine V0/Is using nodal analysis.

[Figure: All elements between a top wire and a common bottom wire: (from left) independent current source Is (arrow up), resistor Rs, resistor R1 connected at node V (current Ib flowing down through R1); resistor R2 in the top wire from node V to the output node V0; at the output node a dependent current source μIb (arrow down) and resistor R3 to the bottom wire; output terminal V0. R1=R2=R3=Rs=1, μ=3] [2007/10m/1a(ii)]

  1. For the network shown below, Find the current ratio transfer function given by α=I2/I1.

[Figure: Ladder network between a common bottom (ground) wire and a top wire, from left to right: current source I1 (arrow up) feeding the top wire with current I1 (arrow to the right); 1 Ω shunt resistor to ground; series dependent voltage source 2I1 (diamond, − on the left, + on the right) in the top wire; 1 Ω shunt resistor to ground carrying current Ic (arrow upwards); series 2 Ω resistor in the top wire; shunt dependent current source (diamond, arrow upwards) labelled Ic/2 [?]; current I2 flowing leftwards in the top wire from the right end into this node; 1 Ω shunt resistor to ground at the right end.] [2005/10m/4a(i)]

1.3] Network theorems

30 questions

  1. In the circuit shown below, Vs is the ac voltage source given by Vs=Vocosωt, with Vo=14.14V and ω=300rad/sec. Calculate the value of load resistance RL for maximum power transfer and also find out maximum power transferred to load.

[Figure: Primary loop: ac source Vs (ω=300 rad/sec.) in series with R1=40 ohms and the primary winding of an ideal-coupled transformer; secondary winding connected across load RL. Dot marks at the top of both windings. Transformer data: k=1, n=0.2 (Turns Ratio)] [2025/10m/4c]

  1. In the circuit diagram given here, load resistance RL is to be set for maximum power transfer. Draw Thevenin equivalent circuit across ab and calculate the value of RL for maximum power transfer. Also calculate the power loss in resistance R3, when the circuit is delivering maximum power to load RL:

[Figure: 9 V source (+ at top) on the left between the bottom rail (b side) and the top-left node; R1=12Ω from the top-left node to node P; from P down to the bottom rail: R2=12Ω in series with a 3 V source (+ at top, towards R2). From P a dependent voltage source 2Vab (diamond, − on the left/P side, + on the right) to node a. R3=4Ω from node a to the bottom rail (node b); variable load resistor RL across a–b; Vab marked between terminals a and b.] [2024/20m/4a]

  1. Obtain Norton equivalent circuit at terminals ab of the coupled circuit shown in the figure. Using it, find out the current passing through 5 Ω resistor connected between the terminals ab.

[Figure: Left source 10∠0∘ V (+ at top) and right source 10∠90∘ V (+ at top), both returning to a common bottom wire. From the top of the left source: 4 Ω in series with coil j8Ω to the middle node, which is brought out as terminal a; from the middle node: coil j4Ω in series with 2 Ω to the top of the right source. Terminal b is taken from the bottom wire. The two coils are magnetically coupled with mutual reactance j5Ω; dot on the j8Ω coil at its left (4 Ω) end and dot on the j4Ω coil at its right (2 Ω) end.] [2023/10m/1a]

  1. Obtain the Thevenin’s equivalent of the network shown in Figure 2(a)(ii), across the terminals XY.

[Figure: Figure 2(a)(ii): A 4 V source (+ terminal on top) on the left, its top connected through a 2 kΩ resistor to a middle top node; from the middle top node a 3 kΩ resistor goes to terminal X. A dependent current source Vx4kΩ (diamond, arrow pointing up) is connected from the bottom wire up to the middle top node. The bottom wire joins the − terminal of the 4 V source, the dependent source and terminal Y. Vx is the voltage across the terminals, + at X and − at Y.] [2022/10m/2a(ii)]

  1. Using the superposition theorem find the voltage ‘V’ across the 5 Ω resistance in the circuit as shown in Figure 6(c).

[Figure: Figure 6(c): Four parallel branches between a top wire and a bottom wire, from left to right: a 2 A current source (arrow pointing up, i.e. current delivered into the top-left node); a 5 Ω resistor with voltage V across it, + at the top; then the top-left node connects through a 10 Ω resistor (in the top wire) to the top-right node; a 2 Ω resistor from the top-right node to the bottom wire; a 4 A current source (arrow pointing up) from the bottom wire to the top-right node. The bottom wire is common to all branches.] [2022/10m/6c]

  1. Find the Thevenin’s equivalent of the circuit shown in Figure 2(a) below as seen from the load impedance ZL. Also find the value of ZL for maximum power transfer.

[Figure: Figure 2(a): Source 100∠0∘ on the left. From its top terminal a −j2Ω capacitor goes right to the dotted top end of coil j4Ω; coil j4Ω runs down to a middle node. A second coil j9Ω runs from the middle node up to its dotted top end, which connects through a j2Ω inductor along the top wire to the right and down through the load ZL to the bottom wire. The two coils are magnetically coupled with k=0.5 (dots at both top ends). From the middle node, 2 Ω in series with j3Ω goes down to the bottom wire, which returns to the source.] [2021/20m/2a]

  1. For the circuit shown in Figure 3(b), calculate the voltage V0(t) as function of time, where V(t)=10sin(6t+60∘)V and I(t)=5cos(4t+30∘)A.

[Figure: Figure 3(b): AC source V(t) on the left; from its top a 10 Ω resistor to node V0. A 0.1 F capacitor from node V0 to the bottom wire, voltage V0 across it (+ at top). Node V0 is joined along the top wire to a current source I(t) connected from the bottom wire up to the top wire (arrow pointing up). From there a 4 H inductor goes right to the + terminal of a 20 V dc source, whose − terminal is on the bottom wire. The bottom wire is common.] [2021/20m/3b]

  1. An electrical network is fed by two ac sources, as shown in Figure 3(b)(ii). Given that Z1=(1−j)Ω, Z2=(1+j)Ω and ZL=(1+j0)Ω. Find the values of Thevenin voltage and impedance across terminals X and Y.

[Figure: Figure 3(b)(ii): Source V1=30∠45∘V (+ at top) in series with Z1 to node X; source V2=30∠−45∘V (+ at top) in series with Z2 to node X; ZL connected between node X and node Y; node Y is the common bottom wire joining the lower terminals of both sources] [2020/10m/3b(ii)]

  1. In the network shown in Figure 1(a), determine the following: (i) The value of the load resistance to have maximum power transfer (ii) The maximum power delivered to the load.

[Figure: Figure 1(a): 5 V dc source (+ at top) in series with R1=3Ω to a middle node; R2=3Ω from the middle node to the bottom wire; from the middle node R3=4Ω to terminal a; variable load resistor RL connected between terminals a and b; terminal b on the bottom wire, which returns to the − terminal of the source] [2019/10m/1a]

  1. Using Thevenin’s theorem, find the current through the 40 Ω resistor connected between terminals a and b in Figure 5(e).

[Figure: Figure 5(e): Bridge circuit fed by a 220 V battery in the left branch (long/positive plate at the top). Battery positive terminal connects through the top rail to two resistors: 3 kΩ from the top rail down to node a, and 400 Ω from the top rail down to node b. 1 kΩ from node a down to the bottom rail; 600 Ω from node b down to the bottom rail; bottom rail returns to the battery negative terminal. 40 Ω resistor connected between terminals a and b] [2018/10m/5e]

  1. For the circuit shown in Fig. 1(a), find the current through 5 Ω resistor by using Thevenin’s theorem and verify the same by using superposition theorem.

[Figure: Fig. 1(a): Two sub-networks joined by two links. Left sub-network between node A (top) and node D (bottom), three branches in parallel: E1=100 V battery (+ at top); a 20 Ω resistor; E2=40 V battery (+ at top) in series with a 6 Ω resistor. Right sub-network between node B (top) and node C (bottom), three branches in parallel: E4=20 V battery (+ marked at its lower terminal) in series with a 7 Ω resistor below it; E5=50 V battery (+ at top); E6=30 V battery (+ marked at its lower terminal) in series with a 4 Ω resistor below it. A 5 Ω resistor connects A to B (top link). Bottom link from D to C: battery E3=20 V (+ on the side towards D) in series with a 10 Ω resistor] [2017/10m/1a]

  1. In the network shown in Figure, determine the value of current through 1 Ω resistance connected between terminals A and B. Verify the answer using superposition theorem also.

[Figure: 4 V source (+ at top) on the left between the top wire and the bottom wire; 2 Ω resistor in the top wire from the source to the middle node; a 2 A current source (arrow pointing up) from the bottom wire to the middle node; 3 Ω resistor in the top wire from the middle node to terminal A; 1 Ω resistor between terminal A and terminal B, B being on the bottom wire] [2015/20m/4b]

  1. Obtain the Norton’s equivalent circuit at the terminals A and B for the network shown in Fig. 3.

[Figure: Fig. 3 – Network with top rail and bottom rail (bottom rail ends at terminal B). Leftmost branch: 1 Ω resistor in series with a 100 V source (+ terminal toward the 1 Ω, i.e. upper end), connected between top-left node P and the bottom rail. Middle branch: 10 Ω resistor from node P to the bottom rail. From node P along the top rail: a 20 V source (– terminal at the P side, + terminal to the right) in series with a 2 Ω resistor to node Q, which connects to terminal A. Right branch: 10 Ω resistor from node Q to the bottom rail (B).] [2014/20m/4b]

  1. Using Δ-Y substitution, determine the resistance between a and d, in Fig. 1.

[Figure: Fig. 1 – Bridge (diamond) network with nodes a (top), b (left), c (right), d (bottom): 2 Ω between a and b; 2 Ω between a and c; 1 Ω between b and c (horizontal diagonal); 2 Ω between b and d; 1 Ω between c and d.] [2013/10m/1a]

  1. Consider the unbalanced Wheatstone bridge shown in Fig. 3: The internal resistance of the galvanometer is 1 ohm. Using Thevenin’s theorem, determine the galvanometer current.

[Figure: Fig. 3 – Wheatstone bridge with nodes a (left), c (top), b (right), d (bottom): 100 Ω between a and c; 110 Ω between c and b; 100 Ω between a and d; 90 Ω between d and b; galvanometer G between a and b. Source E = 10 V (arrow pointing up, i.e. + toward the top) connected by the outer wires between c (top) and d (bottom).] [2013/20m/2a]

  1. (i) Find Y and Z parameters for the following circuit: (ii) State Tellegen’s theorem for network analysis.

[Figure: Two-port: from the upper port-1 terminal (+, current I1 entering) a current-controlled voltage source 5I2 (diamond, + on the port-1 side, − on the right) in series to a node X; node X is connected directly (short circuit) to the lower common wire (node shown by a small circle); from node X a 2 Ω resistor to the upper port-2 terminal (+, current I2 entering); V1 across port 1, V2 across port 2; the lower wire is common to both ports] [2012/20m/3a]

  1. Using Millman’s theorem, find the current I in the 10-ohm resistor in Fig. 2 (a).

[Figure: Fig. 2 (a): Ladder network with a common bottom (return) wire. Left branch: voltage source E1 = 24 V (arrow upwards). From the top of E1 a 2 Ω resistor to node P. Branch from P to the bottom wire: voltage source E2 = 20 V (arrow upwards) in series with a 2 Ω resistor. From P a 2 Ω resistor to node Q; a 9 Ω resistor from Q to the bottom wire. From Q a 1 Ω resistor to node R; the 10 Ω resistor from R to the bottom wire, carrying current I (downwards)] [2011/20m/2a]

  1. State and prove maximum power transfer theorem. [2011/20m/2b]

  2. Use Thevenin’s theorem to find the current in 4 Ω branch of the network given in Fig. 4:

[Figure: Fig. 4 – Left: 12 V source (+ at top) with current I1 flowing from its + terminal through a 5 Ω resistor to node X; 12 A current source from the bottom (reference) line up into node X; from node X a current-controlled voltage source 10I1 (diamond, + on the node-X side, − on the right) in series with the 4 Ω resistor, then a 1 Ω resistor, then a 20 V source (+ at top, − to the bottom line); the bottom line joins all the negative terminals] [2010/10m/2a(i)]

  1. For the network shown below, determine RL which will receive maximum power.

[Figure: Left: 15 V source (+ at top) with current I1 flowing from its + terminal through a 5 Ω resistor to node X; 10 A current source from the bottom line up into node X; from node X a current-controlled voltage source 10I1 (diamond, + on the node-X side, − on the right) in series with the load RL (between two terminals), then a 1 Ω resistor and a 10 V source (+ at top, − to the bottom line); the bottom line joins all the negative terminals] [2009/8m/6a(ii)]

  1. Use Thevenin’s theorem to replace the three-loop circuits of figure by a single-loop equivalent circuit in which the identity of RL is preserved. [2007/10m/6a(i)]

  2. Find the value of RL so that the maximum power is consumed in it.

[Figure: Three-loop ladder with a common bottom wire: on the left a 60 V battery (+ at top) between the bottom wire and the top-left corner; top wire: 60 Ω from the top-left corner to node A; 30 Ω from node A to the bottom wire; from node A along the top wire a 50 V battery (+ terminal towards the right) in series with RL to node B; 60 Ω from node B to the bottom wire; from node B a 40 Ω resistor in the top wire to the top-right corner; a 100 V battery (+ at top) between the top-right corner and the bottom wire] [2007/10m/6a(ii)]

  1. State and explain Thevenin’s theorem and replace the active network of the figure given below, at terminals ab with a Thevenin’s equivalent.

[Figure: Voltage source V = 10∠0∘ (+ at top) on the left; from its + terminal a 5 Ω resistor in the top wire to node X; from node X to the bottom wire a 3 Ω [?] resistor in series with an inductive reactance j4 Ω; from node X an inductive reactance j5 Ω in the top wire to terminal a; terminal b on the bottom wire, which returns to the − terminal of the source] [2006/10m/1a(i)]

  1. If an impedance ZL is connected across a voltage source V with source impedance Zs, then for maximum power transfer, what will be the load impedance? [2004/4m/1a(ii)]

  2. Determine the current in the 5 ohm resistor using Thevenin’s theorem.

[Figure: Ladder circuit: 50 V d.c. source on the left (+ at top) between the top wire and the bottom (return) wire; 1 Ω resistor in the top wire from the source to node 1; 5 Ω resistor from node 1 to the bottom wire; 1 Ω resistor in the top wire from node 1 to node 2; 1 Ω resistor from node 2 to the bottom wire; on the far right a current source of 8 A [?] (arrow pointing up, i.e. driving current from the bottom wire into node 2) connected between the bottom wire and node 2, in parallel with the last 1 Ω resistor] [1999/20m/1b]

  1. Find X and; [?] in terms of R and R2 to give maximum power dissipation in R2 shown in the figure.

[Figure: a.c. source in series with resistor R1; then a shunt reactance X1 (inductor) across the line; then a series reactance X2 followed by the load resistor R2 across the line] [1998/20m/5b]

  1. Calculate the power fed to the 15 Ω resistor by using Thevenin’s equivalent circuit for the portion to the left of points A and B in the circuit of Fig. 2 (b).

[Figure: Fig. 2 (b): Left loop: 100 V source (+ at top); 6.8 Ω resistor in the top line (voltage Vs marked across it); then a 4 Ω resistor and an 18 Ω [?] resistor each connected from the top line to the bottom line. Right part (not wired to the left part): a dependent current source 0.147Vs (arrow upwards) from the bottom line to the top line; 4.8 Ω in the top line; a 10 Ω resistor from the top line to the bottom line; 10 Ω in the top line to terminal A; 15 Ω resistor between A and B; 6 Ω in the bottom line from B back to the bottom line of the source] [1997/20m/2b]

  1. Using Thevenin’s theorem, determine the current in the 2 Ω resistor in the circuit of Fig. 1c.

[Figure: Fig. 1c: Four parallel branches between a top line and a bottom (common) line. Branch 1 (left): voltage source 24 V [?] (+ at top) in series with an 8 Ω [?] resistor in the top line, the resistor joining the source to the top line node of branch 2. Branch 2: current source 2 A (arrow upwards) in parallel with a 20 Ω resistor, connected between the top and bottom lines. Branch 3: 10 Ω resistor in series with a battery of 36 V [?] (label blurred; plate polarity not legible), from the top line to the bottom line. Branch 4 (right): 2 Ω resistor between terminals A (top) and B (bottom), connected across the top and bottom lines] [1996/20m/1c]

  1. Show that an n-mesh, passive, three-terminal network may be replaced by a delta-connection of three impedances. Here n can be arbitrarily large. [1996/20m/2b]

  2. The two figures show a linear reciprocal 2-port network N under two different terminal conditions. The switches are closed at t=0 in both the circuits with zero initial conditions in N. Given that the currents in (i) for t>0 are: i1=0.5(e−t+e−3t) amps; i2=0.1(3e−3t−e−t) amps, find v1(t) for t>0 in (ii).

[Figure: Fig. Q2(b): (i) A 1 V battery connected through a switch (closed at t = 0) to port 1 (terminals 1–1′) of network N, input current i1 entering terminal 1; port 2 (terminals 2–2′) short-circuited, with current i2 in the short (arrow downwards from 2 towards 2′). (ii) Port 1 (1–1′) open-circuited, voltage v1 across it (+ at terminal 1); a 2 V battery connected through a switch (closed at t = 0) across port 2 (2–2′)] [1995/20m/2b]

1.4] Transient analysis

20 questions

  1. For the circuit shown below, steady state is achieved with switch K open. At t=0, switch K is closed. Find the time expression of current in RL. Also find its initial and final values:

[Figure: 50 V voltage source (+ at top) on the left between the bottom rail and the top-left node; 5Ω resistor in the top wire from the top-left node to node P; from node P to the bottom rail a 20Ω resistor in series with a 1 H inductor; from node P along the top wire, switch K (closes at t=0) to the top of RL=20Ω, whose lower end is on the bottom rail] [2026/10m/3a(i)]

  1. In the circuit shown in the diagram, initially key K1 is closed and capacitor has no charge (at time t=0). Now at time t=10 seconds, key K1 is opened and at t=18.68 seconds it is again closed. Plot output voltage across the capacitor with respect to time and find output voltage values at time 10 seconds, 18.68 seconds and 28.68 seconds.

[Figure: Bottom rail = terminal A (grounded). Node M (middle) and top node T. Between M and T: 5Ω resistor (left) and, in parallel, a 1 A current source (arrow up, from M towards T). Between the bottom rail and M: key K1 (left) and, in parallel, a 0.1 A current source (arrow up, from the bottom rail towards M). From T along the top: 95Ω resistor, then a 5 V source (− on the left, + on the right) to node B (output terminal B). Capacitor C=0.1F from B to the bottom rail; OUTPUT taken between B and A] [2025/20m/2a]

  1. In the circuit given here, D1 is an ideal diode and key K1 is ON for a long period of time. Now at time t0, key K1 is opened. Draw the voltage waveform on capacitor C1 and find the final steady-state voltage on the capacitor:

[Figure: 9 V source (+ at top) on the left; from its + terminal, inductor L=10mH along the top to node N. From node N down to the bottom rail: key K1 (marked “Open at t0”) in series with R1=0.9Ω. From node N the top wire continues through diode D1 (anode at N, cathode to the right) to the top of capacitor C1=100μF, whose lower plate goes to the bottom rail, which returns to the − terminal of the 9 V source.] [2024/10m/1e]

  1. In the series RLC circuit shown in the figure, the capacitor has an initial charge Q0=1mC and the switch is in position 1 long enough to establish the steady state. Find the transient current which results when the switch is moved from position 1 to 2 at t=0.

[Figure: The switch pole is connected along the top wire (current i0, arrow to the right) through 5 Ω and 0.1 H in series down to the bottom wire. Position 1 connects the pole to a 10 V source (+ at top) whose − terminal is on the bottom wire; position 2 connects it to a 200 μF capacitor carrying initial charge Q0 (− on the upper plate, + on the lower plate) whose lower plate is on the bottom wire.] [2023/10m/5e]

  1. For the circuit shown in Figure 2(a)(i), initial current through the coil is zero. The switch is closed at time t=0. Find the time domain expression of current flowing through the coil for t≥0. How long will it take for the coil current to reach 95% of its final value and what is the final value of this current?

[Figure: Figure 2(a)(i): Left branch: 100 V source (+ terminal on top) in series with a 50 Ω resistor above it; the top of the 50 Ω resistor connects through switch S (closes at t=0) along the top wire to the right. Middle branch: 100 Ω resistor from the top wire to the bottom wire. Right branch: 4 H coil from the top wire to the bottom wire, coil current iL(t) marked by an arrow pointing down. The bottom wire joins the − terminal of the source, the 100 Ω resistor and the coil.] [2022/10m/2a(i)]

  1. For the circuit shown in Figure 5(e), vC(0+)=2V and i(0+)=23A. Calculate the value of vC(t) for t>0.

[Figure: Figure 5(e): Three branches between a top wire and a common bottom wire. Left branch: capacitor C1=0.5F with voltage vC (+ at top). Middle branch: dependent current source i2 (arrow pointing up). From the top of the middle branch a 3 Ω resistor runs along the top wire to the right branch. Right branch: capacitor C2=13F, with current i in this branch marked by an arrow pointing up (towards the 3 Ω resistor).] [2021/10m/5e]

  1. The switch shown in Figure 1(a) has been closed for a very long time and it is opened at time t = 0. (i) Find the value of iL for t<0. (ii) Just after the switch is opened, find the value of iL(0+). (iii) Determine the expression for iL(t) for t>0 and find the value of iL(∞).

[Figure: Figure 1(a): Three-branch circuit between a top wire and a bottom wire. Left branch: 100 V dc source, + terminal at top, connected through a 20 Ω resistor (in the top wire) to the top middle node. Middle branch (from the top middle node to the bottom wire): switch (opens at t = 0), 5 Ω resistor and a 100 V dc source in series, the source’s − terminal towards the 5 Ω resistor (top) and + terminal at the bottom wire. Right branch: 0.5 H inductor from the top wire to the bottom wire, current iL flowing downward through it] [2020/10m/1a]

  1. Determine current i(t) in the circuit of Figure 5(d), for all values of time.

[Figure: Figure 5(d): Left branch: 100 V dc source (+ at top) between the bottom wire and the top-left corner; top wire: a voltage source 100u(t)V (− on the left, + on the right) in series with a 5 Ω resistor to the top-right node; from the top-right node to the bottom wire two parallel branches: a 5 Ω resistor and a 10 H inductor carrying i(t) downward] [2019/10m/5d]

  1. Consider the R-L-C circuit shown in Fig. 3(c), wherein IS=10A,R=2Ω,L=1H,C=0.5μF,iL(0−)=0 Determine v(0+), dvdt(0+) and d2vdt2(0+) after the switch is closed.

[Figure: Fig. 3(c): Current source IS (arrow pointing upwards) in the left branch; a switch in the top wire closes at t=0, connecting the source to three parallel branches: resistor R (current iR downwards), inductor L (current iL downwards) and capacitor C (current iC downwards); voltage v across the parallel combination marked on the right by a double-headed arrow spanning the top and bottom wires (no polarity marked)] [2017/10m/3c]

  1. In Fig. 5, capacitor C1 is initially charged at 100 V and the other two capacitors are initially uncharged. The switch S is closed at time t=0. Find the current flowing through the resistor as a function of time.

[Figure: Fig. 5 – C1 = 1 μF (left), C2 = 1 μF (middle) and C3 = 2 μF (right), each between the top wire and a common bottom wire. Switch S in the top wire between C1 and C2; resistor R = 500 Ω in the top wire between C2 and C3.] [2013/10m/2c]

  1. The switch S is closed at t=0 in Fig. 2 (c). Using Laplace transforms, find i1(t), i2(t) and the voltage across the inductance.

[Figure: Fig. 2 (c): 12 V battery (current i1 leaving its upper terminal) in series with switch S and a 2 Ω resistor to node N; a 2 Ω resistor from N to the bottom (return) wire; from N a second branch carrying i2 through a 2 Ω resistor in series with a 12 H inductor to the bottom wire, which returns to the battery] [2011/20m/2c]

  1. Determine the time constant for the network shown in Fig. 1:

[Figure: Fig. 1 – 10 V battery in series with switch S and resistor R; beyond R the circuit splits into two parallel branches, resistor 2R and capacitor C, each connected back to the other terminal of the battery] [2010/5m/1a(i)]

  1. In the circuit shown below (Fig. 8), the switch S is in position ‘1’ long enough to establish steady-state conditions and at t=0 is switched to position ‘2’. Draw ‘s-domain’ network:

[Figure: Fig. 8 – Switch S at the top left has its common terminal connected along the top line to a 25 Ω resistor in series with a 2 H inductor down the right side to the bottom line; position 1 connects to a 50 V battery (long plate, i.e. + terminal, towards the switch) whose other end goes to the bottom line; position 2 connects to a 100 V battery (drawn with the long plate, i.e. + terminal, towards the bottom line) whose other end goes to the bottom line; switch shown at position 1 with an arrow indicating movement to position 2] [2010/5m/5a(iii)]

  1. Determine the currents i1, i2 and i4 at t=0+ for the circuit given below. Assume that the voltage source is applied at t=−∞.

[Figure: d.c. source Vs (battery) on the left; current i1 flows from its upper terminal through R2 in the top wire to node P; from node P a vertical branch: R1 (current i2 flowing down) to node Q, then inductor L (current i4 flowing down) from node Q to the bottom wire; from node P along the top wire to the right-hand vertical branch: capacitor C1 from the top wire to node S and capacitor C2 from node S to the bottom wire; a switch marked t = 0 connected between node Q and node S; the bottom wire returns to the lower terminal of Vs] [2006/10m/1a(ii)]

  1. Find iL(0+), VC(0+), dVc(0+)dt and diL(0+)dt for the circuit shown below. Use dVC(0+)dt to denote dVC(t)dt|t=0+. Assume the switch 1 has been opened for switch 2 has been closed for along time and steady-state condition prevails at t=0−.

[Figure: 10 V source (+ at top) in the left vertical branch; from its top terminal a 1 Ω resistor in series with Switch 1 (operated at t = 0) leads to node X; capacitor VC, ½ F (+ at top) from X to the bottom (ground) wire; a second 1 Ω resistor from X to node Y; 1 H inductor from Y to ground carrying iL (arrow downwards); a separate upper branch from X to Y consists of a 2 A current source (arrow pointing right, towards Y) in series with Switch 2 (operated at t = 0). The bottom wire is common to the source, capacitor and inductor.] [2005/6m/2a(i)]

  1. Find the current i(t) through the 8 Ω resistor of the circuit diagram shown below with initial current i(0−)=5 Amp.

[Figure: Single series loop: voltage source 6u(t) (+ at top, arrow upwards) on the left; inductor L = 4 H in the top wire; resistor R = 8 Ω on the right side; bottom wire returns to the source; loop current i(t) clockwise.] [2004/6m/2a(ii)]

  1. Circuit diagram shown below is initially under steady-state condition, the switch is moved from position 1 to position 2 at t = 0. Find the current after switching.

[Figure: 10 V battery on the left, its positive terminal connected by the top wire to switch contact 1; the switch blade is connected (common terminal) to one end of resistor R2 (value illegible under the watermark) [?]; the other end of R2 goes to the top of inductor L = 5 H, whose bottom goes to the bottom wire; switch contact 2 is connected through resistor R1 (value illegible under the watermark) [?] to the bottom wire, which also returns to the battery negative terminal; the switch moves from 1 to 2 at t = 0; current i(t) marked clockwise in the loop R2–L–R1.] [2004/8m/5a(i)]

  1. In the circuit shown below the switch ‘S’ closes at t = 0, and open after 10 ms. What will be the currents in R1 and L1 and L2, and voltage across C1 8 ms after switch ‘S’ opens? Assume D1 to be an ideal diode and a 0.7 V drop across D2 whenever it conducts.

[Figure: 200 V battery in the left vertical branch; from its top terminal the switch S, then inductor L1=0.5 H in the top wire, with diode D2 (unlabelled in the figure) connected in parallel across L1 (its cathode towards the switch side, anode towards the right); the top wire continues to the right and down through R1=50Ω to node N; from N, inductor L2=0.5 H down to the bottom wire; also from N, a branch of capacitor C1=1.0μF in series with diode D1 down to the bottom wire (D1 anode at the bottom wire, cathode towards C1); the bottom wire returns to the battery.] [2003/20m/4a]

  1. In the circuit of Fig 2 (c), when the switch is closed t=0, it is noticed that i(0+)=10 mA and vab(t)=0, t≥0 sec. Assuming zero initial current for inductor and zero initial charge for capacitor, find the values of and R1 and L.

[Figure: Fig. 2 (c): 5 V battery with a switch in the top line feeding two parallel branches: left branch R1 in series with capacitor C = 5 μF (node a between them); right branch inductor L in series with R2=200Ω (node b between them); vab is the voltage between a and b] [1997/20m/2c]

  1. A series R-L circuit with R=50Ω and L=0.2 H has a sinusoidal voltage v(t)=75sin(500t+0.785) applied at t=0, t being taken in sec. Find the complete current for t>0. What is the current at t=0+? Why? [1996/20m/2a]

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1.5] Sinusoidal steady state and resonance

21 questions

  1. Find the values of R and C in the figure shown below, so that Vb=3Va, also V¯b and V¯a are in quadrature. Find also the phase relation between V and Vb, and Va and I:

[Figure: Series circuit: 6Ω resistor in series with a 0.0255 H inductor (current I marked by an arrow flowing left to right after the inductor), then a junction point, then resistor R in series with capacitor C. Voltage Vb is marked across the 6Ω + 0.0255 H section, Va across the R + C section, and the total V=240V, 50 Hz across the whole series combination] [2026/10m/2a(i)]

  1. A circuit consists of a resistor, a variable inductor and a capacitor, all in series. When the circuit is connected across a 300 V, 50 Hz supply, the maximum current is recorded as 0.3 A by varying the inductor. The voltage across the capacitor is then recorded as 900 V. Determine the resistance, inductance and capacitance of the circuit. [2026/10m/5e]

  2. Determine the expressions of currents i1 and i2 in time domain for the circuit shown in Figure 2(a).

[Figure: Figure 2(a): AC voltage source 10cos310tV (+ at top) in series with a 5 Ω resistor (current i1 flowing to the right) to a middle node; 6 mH inductor from the middle node to the bottom wire; from the middle node a 500 μF capacitor (current i2 flowing to the right) to the + terminal of a dependent voltage source 3i1 (+ at top) whose other terminal is on the bottom wire] [2019/20m/2a]

  1. For the circuit shown in Figure 8(a), v(t)=311.12sin377t volts: (i) Find the values of I‾1, I‾2, I‾3, I‾4 and I‾5. (ii) Also compute V‾bc and V‾cd. (iii) Compute the power supplied by the source. (iv) Find the line power factor.

[Figure: Figure 8(a): AC source v(t) (+ at top) in the left branch between the top rail and the bottom rail. Current I‾5 flows from the source along the top rail to node a. From node a, current I‾4 flows down into a parallel combination of inductor L1=0.096H (current I‾1) and capacitor C1=73.3μF (current I‾2, downwards), whose lower ends connect to the bottom rail. From node a a 4 Ω resistor (current I‾3 flowing to the right) leads to node b; from b a 0.096 H inductor leads down to node c; from c a 73.3 μF capacitor leads down to node d on the bottom rail, which returns to the source] [2018/20m/8a]

  1. An industrial consumer is operating a 1 kW induction motor at a lagging power factor of 0.8 and at a source voltage of 200 V r.m.s. In order to reduce expenditure on power consumption, he wishes to raise the power factor to 0.95 lagging by connecting a circuit element in parallel with the load. Indicate the type of the circuit element (inductive or capacitive) and find the value if the operating frequency is 50 Hz. [2017/10m/5b]

  2. Two impedances Z1=5Ω and Z2=(5−jXC)Ω are connected in parallel and this combination is connected in series with Z3=(6.25+j1.25)Ω. Determine the value of capacitance of XC to achieve resonance if the supply is 100 V, 50 Hz. [2016/10m/1e]

  3. For the circuit shown in Figure, evaluate the current through and the voltage across each element.

[Figure: a.c. source 173.2∠0∘ V (+ at top) feeding, through a series 10 Ω resistor (current I), node V1; from V1 two parallel branches to the bottom (return) wire: a 20 Ω resistor carrying I1 (downwards) and a capacitor of reactance −J11.55Ω carrying I2 (downwards)] [2015/10m/1a]

  1. Derive the expressions for instantaneous and average power in a single-phase ac circuit. [2015/10m/1c]

  2. Show that there can be no value of RL in the circuit given in Fig. that will make it resonant.

[Figure: Two input terminals (top and bottom) feeding two parallel branches: branch 1 – variable resistor RL in series with an inductor of reactance j10 ohm; branch 2 – a 4 Ω resistor in series with a capacitor of reactance −j5] [2012/20m/2a]

  1. Determine the resonant frequency of the following circuit (Fig. 6):

[Figure: Fig. 6 – Series loop: a.c. source, 10 Ω resistor, and a parallel combination of (4 H inductor in series with 1 F capacitor) and a 1 F capacitor] [2010/6m/4a(i)]

  1. Compute the quality factor of an RLC series circuit with R = 20 Ω, L = 50 mH and C = 1 μF using Q=ω0LR, 1ω0CR, ω0β [2006/5m/4a(i)]

  2. Find the current I in the circuit shown below.

[Figure: Source vs(t)=40sin3000t on the left; current I flows through a 1.5 kΩ resistor in the top wire to node A; inductor 13 H from node A to the bottom wire; from node A a 1 kΩ resistor in the top wire to the right-hand branch, a capacitor 16 μF to the bottom wire] [2006/5m/7a(i)]

  1. Find the qualifactor Qp at resonance for the circuit shown below.

[Figure: Four branches connected in parallel between two horizontal bus wires: (1) resistor R; (2) Rcoil in series with Lcoil; (3) capacitor C; (4) voltage source V (+ on the left terminal) delivering current I (arrow upwards on the left vertical wire).] [2005/5m/1a(iv)]

  1. What will be the impedance of a parallel connected LCR network at resonance frequency? [2004/4m/1a(i)]

  2. A sinusoidal voltage source is applied to the parallel RC network as shown in the figure below. Find the energy stored and energy dissipated in the resistor over the interval 0 < t < 0.5 sec.

[Figure: Source 10sin2πt connected across two parallel branches: a 1 μF capacitor carrying iC (downwards) and a 1 kΩ resistor carrying iR (downwards).] [2004/10m/4a(i)]

  1. For the circuit given below, Find the frequency w0 at which the impedance across X, Y reaches a maximum.

[Figure: Source Vs(t)=Vsinwt in the left vertical branch; from its top terminal, terminal X is marked on the top wire, followed by series resistor R1; R1 feeds three parallel branches to the bottom wire: inductor L, capacitor C and resistor R2; the bottom wire returns to the source, with terminal Y marked on it near the source.] [2003/10m/1a(i)]

  1. Find the impedance across X, Y at frequency w0 and the current through the network at that condition. [2003/10m/1a(ii)]

  2. A series resonant circuit has its impedance Z(s)=20(s+1+j10)(s+1−j10)s Find (i) Resonant frequency (ii) Q factor (iii) Band width (iv) Impedance under resonance condition. [2003/20m/5b]

  3. Why do the maximum voltages across the inductance and capacitance in a series R – L – C resonant circuit occur at different values of frequencies? Explain. [2000/20m/4a]

  4. Determine V∠θ so that the circuits (i) and (ii) shown in the above figure are equivalent.

[Figure: Circuit (i): source 100∠0 V (+ at top), 8 Ω resistor in the top wire to a node; from that node to the bottom wire an inductive reactance j4 Ω in parallel with a 4 Ω resistor. Circuit (ii): source 100∠0 V (+ at top), 8 Ω resistor in the top wire, then a second source V∠θ (+ at top) from the end of the 8 Ω resistor to the bottom wire] [1999/20m/3a]

  1. In the a.c. circuit of Fig. Q.1(c), the rms values of different voltages under steady state are: VS=16 V; VR=10 V; V1=10 V; V2=7 V. Find the value of RL

[Figure: Fig. Q 1(c): A.c. source VS in series with resistor R = 16 Ω (voltage VR across it) feeding the input port (voltage V1) of a box marked “LC 2-port network”; the output port (voltage V2) is loaded by resistor RL] [1995/20m/1c]

1.6] Coupled circuits

14 questions

  1. In the circuit shown below, Vs is the ac voltage source given by Vs=Vocosωt, with Vo=14.14V and ω=300rad/sec. Calculate the value of load resistance RL for maximum power transfer and also find out maximum power transferred to load.

[Figure: Primary loop: ac source Vs (ω=300 rad/sec.) in series with R1=40 ohms and the primary winding of an ideal-coupled transformer; secondary winding connected across load RL. Dot marks at the top of both windings. Transformer data: k=1, n=0.2 (Turns Ratio)] [2025/10m/4c]

  1. Obtain Norton equivalent circuit at terminals ab of the coupled circuit shown in the figure. Using it, find out the current passing through 5 Ω resistor connected between the terminals ab.

[Figure: Left source 10∠0∘ V (+ at top) and right source 10∠90∘ V (+ at top), both returning to a common bottom wire. From the top of the left source: 4 Ω in series with coil j8Ω to the middle node, which is brought out as terminal a; from the middle node: coil j4Ω in series with 2 Ω to the top of the right source. Terminal b is taken from the bottom wire. The two coils are magnetically coupled with mutual reactance j5Ω; dot on the j8Ω coil at its left (4 Ω) end and dot on the j4Ω coil at its right (2 Ω) end.] [2023/10m/1a]

  1. Find the Thevenin’s equivalent of the circuit shown in Figure 2(a) below as seen from the load impedance ZL. Also find the value of ZL for maximum power transfer.

[Figure: Figure 2(a): Source 100∠0∘ on the left. From its top terminal a −j2Ω capacitor goes right to the dotted top end of coil j4Ω; coil j4Ω runs down to a middle node. A second coil j9Ω runs from the middle node up to its dotted top end, which connects through a j2Ω inductor along the top wire to the right and down through the load ZL to the bottom wire. The two coils are magnetically coupled with k=0.5 (dots at both top ends). From the middle node, 2 Ω in series with j3Ω goes down to the bottom wire, which returns to the source.] [2021/20m/2a]

  1. Let ω = 1000 rad/sec for the circuit of Figure 3(b)(i) and determine the value of the ratio Vo/Vs, if L1=1mH, L2=25mH and k = 1.

[Figure: Figure 3(b)(i): AC source Vs (+ at top) in series with a 2 Ω resistor feeding coil L1; L1 magnetically coupled (coefficient k) to coil L2, dots at the top ends of both coils; L2 connected across a 40 Ω load resistor with output voltage Vo (+ at top); the bottom ends of the primary and secondary circuits are joined by a common wire] [2020/10m/3b(i)]

  1. Obtain the dotted equivalent circuit for the coupled circuit shown in Fig. 3(a) and hence find the voltage across the capacitor:

[Figure: Fig. 3(a): Two magnetically coupled coils wound on the two vertical limbs of a common rectangular (window-type) core: left coil reactance j5Ω, right coil reactance j5Ω, mutual reactance j2Ω (curved double-headed arrow between the coils); the windings are drawn as mirror images of each other about the core centre-line (winding sense as drawn; no dots given). Left mesh: source 10∠0∘ (+ at top) → 5 Ω resistor in the top wire → top terminal of the left coil. Right mesh: source 10∠90∘ (+ at top) → 5 Ω resistor in the top wire → top terminal of the right coil. The bottom terminals of both coils are joined together by a wire running beneath the core; from the middle of this wire a capacitor −j10Ω goes down to the bottom rail, which joins the − terminals of both sources] [2016/20m/3a]

  1. The applied a.c. voltage and the resulting current in the following circuit (Fig. 7) are in phase. Determine the coefficient of coupling and the dot polarity of coil PQ:

[Figure: Fig. 7 – Series loop: a.c. source, capacitor −j12, resistor 10, coil j8 (dot at its left end, the end nearer the resistor), then coil j2 between terminals P (left) and Q (right), back to the source; mutual coupling coefficient K shown between the j8 and j2 coils; no dot is marked on coil PQ] [2010/4m/4a(ii)]

  1. In the circuit given below, A and B are mutually coupled coils. Determine coefficient of coupling K between them so that the circuit is in resonance.

[Figure: Series circuit between two open terminals: resistor 10, capacitor −j20, coil A (j8) and coil B (j10) in series; coupling coefficient K marked between coils A and B; no dots shown] [2009/5m/1a(ii)]

  1. For the network shown below, write mesh equations in vector-matrix form for the loop currents i1 and i2. Assume mutual inductances between coils L1 & L3 and coils L2 & L3 as M13 and M23 respectively.

[Figure: Two-mesh network. Left mesh: source v(t) (+ at top), R1 and L1 in the top branch to the middle node; the shared middle branch is L3 in series with R2 to the bottom line. Right mesh: L2 in the top branch from the middle node, R3 on the right side down to the bottom line. Mesh currents i1 and i2 both clockwise. Dot markings: round dot at the left (source-side) end of L1 and round dot at the top end of L3 (pair L1–L3); square marker at the right end of L2 and square marker at the top end of L3 (pair L2–L3)] [2009/8m/4a(ii)]

  1. Find the voltage transfer function V2/V1 for the network given below.

[Figure: Source V1sinωt (+ at top) on the left; inductor L1 (dot at its left end) in the top wire to a middle node; capacitor C from the middle node to the bottom wire; inductor L2 (dot at its left end) in the top wire from the middle node to the right; resistor R2 from the right end of the top wire to the bottom wire, output V2 across it (+ at top); mutual inductance M between L1 and L2] [2006/10m/5a(ii)]

  1. Determine v (t) for the circuit shown below when vs=10cos30t V.

[Figure: Source vs (+ at top) in the left branch; from its top terminal a 1/50 F capacitor in the top wire leads to node X; 0.3 H inductor from X to the bottom wire with voltage v(t) across it (+ at top, dot at the top end); from X a 28 Ω resistor leads to the right top corner, from which a 0.2 H inductor (dot at the top end) goes down to the bottom wire; mutual inductance 0.1 H between the 0.3 H and 0.2 H coils (double-headed arrow).] [2005/5m/5a(i)]

  1. Find the input impedance Z of the circuit shown below, ω=1000 rad/s.

[Figure: From the upper input terminal: 8 mH inductor (dot at its input-terminal end) in series with a 1/6 μF capacitor to node X; from X a 6 mH inductor (dot at its top end) to the bottom (lower input terminal) wire, and a 3 Ω resistor also from X to the bottom wire (in parallel with the 6 mH coil); mutual inductance 5 mH between the 8 mH and 6 mH coils; Z is the impedance seen at the input terminals.] [2005/5m/8a(ii)]

  1. The figure shows an equivalent circuit of a small two winding transformer in terms of the primary.

[Figure: T-equivalent circuit referred to the primary, between a pair of input terminals (left) and a pair of output terminals (right) joined by a common bottom wire: on the top line from the left input terminal, 2 Ω resistor in series with 1 H inductor to a junction; from the junction, 1 H inductor in series with 2 Ω resistor to the right output terminal; shunt (magnetising) inductor 24 H from the junction down to the bottom wire. A dashed vertical line through the shunt branch marks “Primary side” (left) and “Secondary side (equivalent)” (right).]

If the self inductance L2 of the secondary is 16 H, estimate the following

(i) The actual winding resistance of the secondary. [2002/6m/1a(i)]

(ii) The secondary open circuit voltage with primary supplied with 220 V a.c. [2002/6m/1a(ii)]

(iii) The mutual inductance M. between the primary and the secondary. [2002/8m/1a(iii)]

  1. Prove that an ideal transformer shown below for which v1/v2=n can be identical with a perfectly coupled transformer.

[Figure: Two magnetically coupled coils with mutual inductance M. Primary: terminals + (top) and − (bottom) with voltage v1 between them; current i1 flows along the top wire (arrow pointing right, towards the coil) into coil L1, whose dotted end is at the top; the bottom of L1 returns to the − terminal. Secondary: coil L2, dotted end at the top, connected by the top wire to the + output terminal and by the bottom wire to the − output terminal, with voltage v2 across the output terminals; current i2 marked on the top wire of the secondary.]

if n=L1/L2, where L1 and L2 are the self inductances of the primary and secondary windings of the transformer and M is the mutual inductance. Discuss about the current ratio. Obtain the expression for i1(t) and conditions that the perfect transformer will be an ideal transformer. [2001/20m/1a]

  1. Two coils A (R1=100 ohm, L1=0.2 H) and B (R2=100 ohm, L2=0.4 H) are coupled by an inductance of 0.2 H. Find the voltage V at a frequency of 1000 rad/s to be applied across coil A to cause a current of 10 milliamperes through coil B across whose terminals a resistance of 100 ohms is connected.

[Figure: Coupled coils: source V in series with R1 and coil L1 (coil A, terminal marked A); coil L2 (coil B, terminal marked B) in series with R2 and a 100 Ω load resistor; mutual inductance M between L1 and L2, dots at the upper ends of both coils] [1998/20m/3a]

1.7] Balanced 3-phase circuits

9 questions

  1. A balanced three-phase supply system with a line voltage of 400 V is supplying a balanced Y-connected load with 1500 W at a leading power factor of 0.8. Determine the line current and the per phase load impedance. Now, a balanced 900 W lighting load is added in parallel to the system. What will be the new line current? [2019/10m/6b]

  2. Derive the expression of total average power in three-phase balanced circuit. [2018/10m/1a]

  3. A 400-V, 3-phase balanced source is connected to an unbalanced Δ-connected load of impedances Z¯ab=10∠+45∘Ω, Z¯bc=10∠0∘Ω and Z¯ca=10∠−45∘Ω. Determine the line currents (in phasor form), total active (real) and reactive powers. [2017/20m/8a]

  4. A three-phase balanced delta-connected load gives wattmeter readings of 1050 W and 550 W, when the two-wattmeter method is applied. Calculate the impedance in each arm of the load. Given, line voltage = 200 V. [2014/10m/1e]

  5. A delta-connected balanced three-phase load is supplied from a three-phase, 400 V supply. The line current is 20 A and power taken by the load is 10000 W. Find (i) impedance in each branch and (ii) the line current, power factor and power consumed if the same load is connected in star. [2014/20m/2b]

  6. For a 3-phase, 400 V, 50 Hz, acb system, write the voltages vac and vbn in instantaneous form, assuming Vbc as a reference phasor. [2010/5m/1a(ii)]

  7. Three identical impedances of 5∠−30∘ ohms are connected in star to a 3-phase, 4-wire, 400 volts cba system. Express the current in phase ‘a’ in phasor form, assuming Vbc as a reference phasor. [2009/5m/1a(iii)]

  8. A balanced three–phase system has a line voltage of 500 V. Two balanced Y-connected loads are present. One is a capacitive load with (7 − j2) Ω per phase, and the other is an inductive load with (4 + j2) Ω per phase. Find (1) the phase voltage; (2) the line current, (3) the total power drawn by the load; (4) the power factor at which source is operating. Draw the circuit arrangement also. [2006/10m/5a(i)]

  9. Find the rms value of current through the switch S when it is closed in the 3-phase circuit shown in Fig. Q. 2(a). Hence find the rms value of voltage across it when S is opened. Z‾1=40+j0 ohms, Z‾2=j80 ohms.

[Figure: Fig. Q 2(a): 3-phase balanced 400 V supply with three line terminals; a star-connected load with impedance Z‾1 in each of the three phases; in the first line, impedance Z‾2 is connected in series between the supply terminal and the Z‾1 of that phase, and switch S is connected across (in parallel with) Z‾2; the other two lines go directly to their Z‾1 arms] [1995/20m/2a]

1.8] Two-port networks

22 questions

  1. Find the y-parameters of the two-port network shown below:

[Figure: Two-port network with common lower rail (terminals 1′ and 2′). Port 1: terminal 1 (+) and 1′ (−), voltage V1, current I1 entering terminal 1. From terminal 1’s node: 1Ω resistor to the lower rail; 2Ω series resistor from terminal 1’s node to node 2 side node; from that node a 2Ω resistor to the lower rail and a dependent current source 3I1 (diamond, arrow pointing down, i.e. current flowing from the upper line to the lower rail) to the lower rail; that node connects to terminal 2 (+), with I2 entering terminal 2 and voltage V2 between 2 (+) and 2′ (−)] [2026/10m/3a(ii)]

  1. Calculate Z-parameters for the two-port network given in the circuit diagram.

[Figure: Bridged-T two-port inside a dashed box. Port 1: V1 (+ upper terminal), current I1 entering the upper terminal and leaving the lower terminal. Port 2: V2 (+ upper terminal), current I2 entering the upper terminal and leaving the lower terminal. Between the upper input node and the upper output node: a 3Ω bridging resistor, and in parallel with it two 3Ω resistors in series whose midpoint is connected through a third (shunt) 3Ω resistor to the common lower line] [2025/10m/1e]

  1. The experimental data for the two-port network shown in the figure is given in the table.

[Figure: Two-port “Network” driven at port 1 by source VS1 (+ at top) with current I1 entering the top terminal of port 1, and at port 2 by source VS2 (+ at top) with current I2 entering the top terminal of port 2.]

VS1 Volts VS2 Volts I1 Amp I2 Amp
Experiment 1 100 50 5 −30
Experiment 2 50 100 −20 −5
Experiment 3 25 0 – –
Experiment 4 – – 5 0

Obtain Z-parameters, Y-parameters and fill in the missing data. [2023/10m/4c]

  1. For a two-port network, the currents I1 and I2 are as given below: I1=2V1−V2 I2=−V1+2V2 Find the transmission and hybrid parameters of the network. [2022/10m/5e]

  2. In Figure 1(a) shown below, the two-port network is characterized in terms of y-parameters with y11=3.3×10−3S, y22=5×10−3S and y12=y21=0. Find the voltage across 200 Ω load.

[Figure: Figure 1(a): AC source 100sin(2t) on the left. From its top terminal a 2 H inductor goes to terminal 1 of the Two-port Network, current I1 entering terminal 1. Terminals 1′ and 2′ of the two-port are joined by a common wire, and from this common wire a 0.01 F capacitor goes down to the bottom wire. Terminal 2 (current I2 entering terminal 2) is connected along the top-right wire to a 200 Ω Load, which goes down to the bottom wire. The bottom wire connects the lower terminal of the source, the capacitor and the load.] [2021/10m/1a]

  1. Find the h-parameters of the two-port circuit shown in Figure 2(a)(i). If the input contains a source voltage with series resistance of 200 Ω, find the output impedance (Zout) of the circuit.

[Figure: Figure 2(a)(i): Two-port network. Input port (terminals V1, + at top): a 1 kΩ resistor and a dependent current source 10−5V2 (arrow pointing upward, towards the top input wire) both connected across the input terminals. Output port (terminals V2, + at top): a dependent voltage source 100V1 (− terminal at top, + terminal at bottom) from the common bottom wire, in series with a 10 kΩ resistor in the top wire leading to the + output terminal. The bottom wire is common to both ports] [2020/10m/2a(i)]

  1. Obtain z-parameters of a two-port network in terms of its ABCD parameters. [2017/10m/5e]

  2. A two-port network has z11=z12=z21=z22=200Ω. Two such networks are connected in cascade. What are the overall z-parameters of the composite network? [2015/10m/3c]

  3. The z-parameters of a two-port network are z11=20Ω, z22=30Ω, z12=z21=10Ω. Find y and ABCD parameters of the network. [2014/10m/3c]

  4. Determine the transmission matrix for the circuit shown and explain why open circuit impedance parameters can not be defined for this circuit.

[Figure: Two-port network: a single series impedance Z connected between the upper input terminal (port 1, +) and the upper output terminal (port 2, +); the lower terminals of the two ports (both −) are joined by a straight wire. V1 across port 1, current i1 entering at the upper port-1 terminal (arrow towards Z); V2 across port 2, current i2 entering at the upper port-2 terminal (arrow towards Z)] [2012/12m/1a]

  1. (i) Find Y and Z parameters for the following circuit: (ii) State Tellegen’s theorem for network analysis.

[Figure: Two-port: from the upper port-1 terminal (+, current I1 entering) a current-controlled voltage source 5I2 (diamond, + on the port-1 side, − on the right) in series to a node X; node X is connected directly (short circuit) to the lower common wire (node shown by a small circle); from node X a 2 Ω resistor to the upper port-2 terminal (+, current I2 entering); V1 across port 1, V2 across port 2; the lower wire is common to both ports] [2012/20m/3a]

  1. The z-parameters of a symmetrical two-port network (consisting of passive elements only) are given by z11=23Ω and z21=13Ω. Obtain equivalent T-network. If this network is excited by a 2-volt source having internal resistance of 1 ohm, determine the load resistance to be connected across port-2 which will receive maximum power. [2010/10m/6a(ii)]

  2. A Bridge-T network is made up of four capacitances, each having a value of 1 farad. Determine y parameters of this network, assuming that this Bridge-T network can be treated as parallel interconnection of two two-port networks. [2009/12m/6a(i)]

  3. List the properties of S-parameters. [2007/5m/5d(iii)]

  4. For the given network shown below driven by a current source and terminated by a resistor R2 at port 2, calculate the transfer functions Z21(s), Y21(s) and the driving point functions Z11(s), Z22(s).

[Figure: Input current source I1(s) (arrow up) connected to port 1 (terminals 1–1′), port voltage V1(s); inside the dashed box labelled 2-Port Network: resistor R1 (current Ia(s), downwards) across port 1, then inductor Ls (current IL(s), towards port 2) in the top wire from terminal 1 to terminal 2; bottom wire straight from 1′ to 2′; port 2 (terminals 2–2′, voltage V2(s), current I2(s) flowing into terminal 2) terminated by resistor R2 labelled Output; the source side labelled Input] [2006/5m/6a(i)]

  1. Design an m-derived π-section high-pass filter having characteristic impedance 600 Ω, cut-off frequency 5 kHz and infinite attenuation at 4 kHz. [2005/10m/7a(ii)]

  2. N1 and N2 are two 2-port networks connected in parallel on both input port side as well as output port side, to form a composite 2 – port network N as indicated.

[Figure: Composite two-port N (dashed box): the pair of input terminals of N (“Input port”) feeds, in parallel, the input port of two-port N1 (upper) and the input port of two-port N2 (lower); the output ports of N1 and N2 are connected in parallel to the pair of output terminals of N (“Output port”).]

N1 and N2 are defined by the Z-parameters as below [ZN1]=[4335]Ω,[ZN2]=[3224]Ω Obtain the Z-parameters for the composite 2-port network N. [2002/20m/8a]

  1. For the pole-zero configuration of an impedance function shown below draw the schematic diagrams of the two Foster and two Cauer networks without determining element values.

[Figure: Pole-zero plot along the jω axis (drawn horizontally, origin at the left on the vertical axis): pole (×) at the origin, then alternately zero (○), pole (×), zero (○), pole (×), and a zero (○) at ω = ∞.]

What more information do you need to determine the element values? [2001/20m/8a]

  1. Obtain Z-parameters of the 2-port network given above and deduce Y-parameters from the result.

[Figure (printed above the text): Ladder two-port: from input terminal 1 (current I1 entering, voltage V1 across port 1) series resistor R to node A; shunt 2R from node A to the common bottom line; series 2R from node A to node B; shunt 2R from node B to the bottom line; series R from node B to output terminal 2 (current I2 entering, voltage V2 across port 2).] [2000/20m/7a]

  1. Determine the condition under which the input impedance of the network shown in the figure below will be equal to R.

[Figure: Two-port: in the upper line a resistor R in series, bridged by an impedance Z2 connected in parallel with it; after it a shunt impedance Z1 from the upper line to the lower line, followed by a shunt resistor R across the output terminals] [1998/20m/8b]

  1. The h-parameters of a 2-port network used in the circuit of Fig. 1a are h11=100Ω, h12=0.0025, h21=20 and h22=1 mS. Find the ratio V2/V1.

[Figure: Fig. 1a: Source Vs (+ at top) in series with a 1 kΩ resistor feeding input port 1 of a box marked “2-PORT NETWORK”; input voltage V1 across port 1 (+ at top); output port 2 (voltage V2, + at top) loaded by RL=2kΩ] [1996/20m/1a]

  1. What do you understand by S-parameters of a 2-port network? Why are these parameters preferred to H, Y and Z parameters for operation in microwave range of frequencies? Show that the S-matrix of a directional coupler may be reduced to the form S=[0p0jqp0jq00jq0pjq0p0] [1996/20m/12a]

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